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Allisa [31]
3 years ago
9

Energy of motion is referred to as CA. thermal energy B. electrical energy C. potential energy D. kinetic energy​

Chemistry
1 answer:
Natali [406]3 years ago
8 0
It’s, D. Kinetic Energy.

Explanation: Energy associated with an object’s motion is called kinetic energy. A speeding bullet, a walking person, and electromagnetic radiation like light all have kinetic energy.

Hope this helped ;)
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Which type of bond is present within a water molecule
krok68 [10]

Answer:

Covalent bonds

Explanation:

3 0
3 years ago
Calculate the concentration of IO−3 in a 1.65 mM Pb(NO3)2 solution saturated with Pb(IO3)2 . The Ksp of Pb(IO3)2 is 2.5×10−13 .
lara31 [8.8K]

Answer:

See explaination

Explanation:

1) Pb(NO3)2 => Pb2+ + 2 NO3-

[Pb2+] = [Pb(NO3)2] = 7.56 mM = 7.56 x 10-3 M

Pb(IO3)2 <=> Pb2+ + 2 IO3-

Ksp = [Pb2+][IO3-]2 = 2.5 x 10-13

7.56 x 10-3 x [IO3-]2 = 2.5 x 10-13

[IO3-] = 5.75 x 10-6 M ≈ 5.8 x 10-6 M

(2) [Pb2+] = 1.7 x 10-6 M

Ksp = [Pb2+][IO3-]2 = 2.5 x 10-13

1.7 x 10-6 x [IO3-]2 = 2.5 x 10-13

[IO3-] = 3.83 x 10-4 M

[IO3-]from Pb(IO3)2 = 2 x [Pb2+]

= 2 x 1.7 x 10-6 = 3.4 x 10-6 M

[IO3-]from NaIO3 = [IO3-] - [IO3-]from Pb(IO3)2

= 3.83 x 10-4 - 3.4 x 10-6

= 3.80 x 10-4 M

NaIO3 => Na+ + IO3-

[NaIO3] = [IO3-]from NaIO3

= 3.80 x 10-4 M ≈ 3.8 x 10-4 M

7 0
4 years ago
Solid cesium iodide has the same kind of crystal structure as CsCl which is pictured below: If the edge length of the unit cell
Assoli18 [71]

The question is incomplete, here is the complete question:

Solid cesium iodide has the same kind of crystal structure as CsCl which is pictured below: If the edge length of the unit cell is 456.2 pm, what is the density of CsI in g/cm^3

The image is attached below.

<u>Answer:</u> The density of CsI is 9.09g/cm^3

<u>Explanation:</u>

To calculate the density of metal, we use the equation:

\rho=\frac{Z\times M}{N_{A}\times a^{3}}

where,

\rho = density

Z = number of atom in unit cell = 2  (BCC)

M = atomic mass of CsI = 259.8 g/mol

N_{A} = Avogadro's number = 6.022\times 10^{23}

a = edge length of unit cell = 456.2pm=456.2\times 10^{-10}cm    (Conversion factor:  1cm=10^{10}pm  )

Putting values in above equation, we get:

\rho=\frac{1\times 259.8}{6.022\times 10^{23}\times (456.2\times 10^{-10})^3}\\\\\rho=9.09g/cm^3

Hence, the density of CsI is 9.09g/cm^3

3 0
3 years ago
=
Alex787 [66]

Answer:

Grinidng chalk into a fine powder

Explanation:

4 0
3 years ago
Read 2 more answers
Is Na2SO4 ionic or covalent
Diano4ka-milaya [45]

Answer: What types of bonds exist between the atoms in a molecule of sodium sulfate, Na2SO4 ? The formula for this compound can be written as [Na+]2[SO42-], the sulfate anion is formed by covalent bonding between sulfur and oxygen. Since there is a bond polarity to a S-O bond these are polar covalent bonds.

Explanation:

3 0
3 years ago
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