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eimsori [14]
3 years ago
10

Is 0.135135135135...... a irrational number?

Mathematics
2 answers:
Elis [28]3 years ago
7 0
It is not an irrational number.  In this number, the pattern is 135 repeating.  Since it repeats in a certain pattern, it is rational.
grigory [225]3 years ago
5 0
An irrational number is a number that cannot be written in the form a/b or fractional form
this is repeating so we can just draw a vinculum over the repeting part (135)
it would be represented as <u />
<u />   ___
0.135

this is a rational number
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What value is equivalent to 34 − 23⋅ (5 − 2) − 60 ?
xxMikexx [17]

Answer:

68-46 x (10-4)-120

Step-by-step explanation:

3 0
2 years ago
A candidate took a phone poll of 110 people. Of the 110 people polled, 87 said they would vote for the other person. There are 9
SSSSS [86.1K]

Option B

7569 number of people are going to vote for the other candidate

<em><u>Solution:</u></em>

Given that candidate took a phone poll of 110 people

Of the 110 people polled, 87 said they would vote for the other person

There are 9570 people in the district

You can set up this problem like a proportion

Let "x" be the number of people who would vote for the other candidate

\frac{87}{110} = \frac{x}{9570}

To solve proportions, you cross-multiply. This means you multiply the numerator by the other denominator, and the denominator by the other numerator

87 \times 9570 = 110 \times x

832590 = 110x

x = 7569

Thus 7569 number of people are going to vote for the other candidate

6 0
3 years ago
Read 2 more answers
A research firm tests the miles-per-gallon characteristics of three brands of gasoline. Because of different gasoline performanc
Anni [7]

Answer:

A.) At α = 0.05, is there a significant difference in the mean miles-per-gallon characteristics of the three brands of gasoline.

B.)<u><em>The advantage of attempting to remove the block effect is</em></u>

The completely randomized designs does not prove that H0 is incorrect only that it cannot be rejected.

Step-by-step explanation:

<em><u /></em>

<em><u>Using Two-way ANOVA method</u></em>

Given problem

<em><u>Observation              I          II       III          Row total (xr)</u></em>

A                              18 21 20            59

B                            24 26 27             77

C                            30 29 34             93

D                            22 25 24            71

<u>E                            20 23 24           63                      </u>

Col total (xc)             114 124 129        367

∑x²=9233→(A)

∑x²c/r

=1/5(114²+124²+129²)

=1/5(12996+15376+16641)

=1/5(45013)

=9002.6→(B)

∑x²r/c

=1/3(59²+77²+93²+71²+67²)

=1/3(3481+5929+8649+5041+4489)

=1/3(27589)

=9196.3333→(C)

(∑x)²/n

=(367)²/15

=134689/15

=8979.2667→(D)

Sum of squares total

SST=∑x²-(∑x)²/n

=(A)-(D)

=9233-8979.2667

=253.7333

Sum of squares between rows

SSR=∑x²r/c-(∑x)²/n

=(C)-(D)

=9196.3333-8979.2667

=217.0667

Sum of squares between columns

SSC=∑x²c/r-(∑x)²/n

=(B)-(D)

=9002.6-8979.2667

=23.3333

Sum of squares Error (residual)

SSE=SST-SSR-SSC

=253.7333-217.0667-23.3333

=13.3333

<u>ANOVA table</u>

Source                 Sums         Degrees      Mean Squares

of Variation       of Squares   of freedom

<u>                               SS                 DF              MS       F p-value</u>

B/ w     SSR=217.0667              4 MSR=54.2667    32.56 0.0001

rows

B/w     SSC=23.3333         c-1=2 MSC=11.6667        7 0.01

columns

<u>Error (residual)SSE=13.3333 (r-1)(c-1)=8 MSE=1.6667                  </u>

<u>Total SST=253.7333 rc-1=14                                                        </u>

Conclusion:

<u> 1. F for between Rows</u>

The critical region for F(4,8) at 0.05 level of significance=3.8379

The calculated F for Rows=32.56>3.8379

Therefore H0 is rejected

<u>2. F for between Columns</u>

The critical region for F(2,8) at 0.05 level of significance=4.459

We see that the calculated F for Colums=7>4.459

therefore H0 is rejected,and concluded that there is significant differentiating between columns

<u><em>Part B:</em></u>

To analyze the data for completely  randomized designs click on anova two factor without replication  in the data analysis dialog box of the excel spreadsheet.

The following table is obtained

Source DF             Sum                  Mean           F Statistic

<u>                 (df1,df2)    of Square (SS) Square (MS)                    P-value</u>

Factor A       1 1496.5444 1496.5444 769.6514          0.001297

Rows

Factor B -     2 19.4444           9.7222               5                  0.1667

Columns

Interaction

AB               2    3.8889   1.9444        0.1013         0.9045

<u> Error     12   230.4            19.2                                           </u>

<u>Total 17 1750.2778 102.9575                                                         </u>

<u />

<u>Factor - A- Rows</u>

Since p-value < α, H0 is rejected.

<u>Factor - B- Columns</u>

Since p-value > α, H0 can not be rejected.

The averages of all groups assume to be equal.

<u>Interaction AB</u>

Since p-value > α, H0 can not be rejected.

<u><em>The advantage of attempting to remove the block effect is</em></u>

The completely randomized designs does not prove that H0 is incorrect only that it cannot be rejected.

3 0
2 years ago
Work out the acceleration for the first 3 seconds?
Finger [1]

The acceleration is given by the slope of the line. This line passes through the points (0, 2) and (3, 5), so it has slope

\dfrac{5-2}{3-0}=1

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5 0
3 years ago
Read 2 more answers
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Helen [10]

Answer:

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Step-by-step explanation:

You can simply multiply all 3 sides to get the cubic volume B x <em>h </em>is the same as<em> l</em> x <em>w </em>x <em>h</em>

<em />

<em>ex. </em>Number 2, length 3, width 2, height 5

Base is<em> 2x3=6 </em>times <em>5 = 30 </em>or<em> 2 x 3 x 5=30</em>

3 0
3 years ago
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