Ask question

Ask question

All categories

3 years ago

13

I have a circle that has a radius of 8 in. What is the circumference of the circle? What is the area of the circle? Explain your

steps.

2 answers:

mariarad [96]3 years ago

7 0

Answer: the radios IS 16

Step-by-step explanation:

Radios IS half circule so

8×2=16

Keith_Richards [23]3 years ago

3 0

Answer:

16

Step-by-step explanation:

You might be interested in

I'm so confused. If you answer, please explain.

Ahat [919]

Answer:

its SAS

Step-by-step explanation:

HF = GF

HGJ angle = FGJ angle

JG = JG

3 0

2 years ago

What is the image of (3,−5) after a reflection over the x-axis?

mihalych1998 [28]

I think it’s gonna be (3,5)

8 0

2 years ago

Find the sine ratio of angle Θ.

charle [14.2K]

Answer:

sometimes

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

You have total coins for a total of $. . You only have quarters and dimes. Let represent the number of quarters and represent th

Sonja [21]

Answer:

$Quarters = 41$

$Dimes = 18$

Step-by-step explanation:

Given

$Coins = 59$

$Worth = \$12.05$

$d = dimes$

$q = quarters$

Required

The number of each coin

The total coins can be represented as:

$d + q = 59$

$1\ quarter = \$0.25 \\ 1\ dime = \$0.10$

So, the worth of the coin is:

$0.25q + 0.10d = 12.05$

The equations to solve are:

$0.25q + 0.10d = 12.05$

$d + q = 59$

Make d the subject in: $d + q = 59$

$d =59 - q$

Substitute $d =59 - q$ in $0.25q + 0.10d = 12.05$

$0.25q + 0.10(59 - q) = 12.05$

$0.25q + 5.9 - 0.10q = 12.05$

Collect like terms

$0.25q - 0.10q = 12.05 - 5.9$

$0.15q = 6.15$

Solve for q

$q=\frac{6.15}{0.15}$

$q=41$

Substitute $q=41$ in $d =59 - q$

$d = 59 - 41$

$d = 18$

So:

$Quarters = 41$

$Dimes = 18$

5 0

2 years ago

Is the equation cosine theta - sine theta =1 an identity? Explain

Lynna [10]

Answer: No, because an identity is an equation that is always true and cos(theta) - sin(theta) does not always equal 1.

Hope this helped! :)

7 0

2 years ago