Question

What equation is the inverse of 2(x-2) ^2 =8(7+y)

Answer 1

Answer:

- Y=2+√4x+28 -

Step By Step:

Ok so, the original expression is 2(x - 2)² = 8(7 + y).

First you Rewrite the expression as 7 + y = (2/8)*(x-2)² = (1/4)*(x-2)²

So know its; y = (1/4)(x-2)² - 7

To find the inverse, switch x and y, and solve for y.

x = (1/4)(y-2)² - 7

Then you Multiply through by 4

4x = (y-2)² - 28

(y-2)² = 4x + 28

y - 2 = √(4x + 28)

y = 2 +/- √(4x + 28)