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Shkiper50 [21]
2 years ago
6

A hardware store rent vacuum cleaners that customers for part or all of A day before returning. The Store charges a flat fee Plu

s an hourly rate. Write a linear function F for the total retail cost of a vacuum cleaner.
Mathematics
1 answer:
Pavel [41]2 years ago
8 0

Answer:

Step-by-step explanation:

Let x represents the amount that the customer pays per hour

for renting the vacuum cleaner before returning it.

Let y represent the flat rate that the store charges a customer for renting the vacuum cleaner.

Let F represent the amount that the store charges a customer for renting the vacuum cleaner for x hours.

A linear function F for the total retail cost of a vacuum cleaner would be

F(x) = x + y

If the customer rents it for n hours, the total amount becomes

F(x) = nx + y

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Angle of 74° with the ground if the foot of the latter 6.5 feet from the wall, how high on the wall is the ladder?
Pie
Tanα=h/x

h=xtanα, we are told that x=6.5ft and α=74° so

h=6.5tan74 ft

h≈22.67 ft  (to nearest hundredth of a foot)
7 0
3 years ago
1. 112<br><br> 2. 136 <br><br> 3. 68 <br><br> 4. 158 <br><br> 5. 129
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Answer:

4. 158

Step-by-step explanation:

First let's make things a little simpler and put these arcs in terms of x.  We know that the degree measure around the outside of a circle, regardless of its size, is 360.  So let's say that arc BC is x.  That means that arc BDC is 360 - x.  This is because arc BC + arc BDC = 360.  Substituting in our x's we have:

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Following the formula then, we have

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Multiply both sides by 2 to get rid of the fraction and get

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Divide both sides by -2 to get that x = 158

Since we are looking for arc BC and we designated arc BC as our x, that means that arc BC = 158.

3 0
3 years ago
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\bf \begin{array}{llccll}&#10;term&value\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;a_1&-4096\\&#10;a_2&-4096r\\&#10;a_3&-4096rr\\&#10;a_4&-4096rrr\\&#10;&-4096r^3\\&#10;&64&#10;\end{array}\implies -4096r^3=64&#10;\\\\\\&#10;r^3=\cfrac{64}{-4096}\implies r^3=-\cfrac{1}{64}\implies r=\sqrt[3]{-\cfrac{1}{64}}&#10;\\\\\\&#10;r=\cfrac{\sqrt[3]{-1}}{\sqrt[3]{64}}\implies \boxed{r=\cfrac{-1}{4}}\\\\&#10;-------------------------------

\bf n^{th}\textit{ term of a geometric sequence}\\\\&#10;a_n=a_1\cdot r^{n-1}\qquad &#10;\begin{cases}&#10;n=n^{th}\ term\\&#10;a_1=\textit{first term's value}\\&#10;r=\textit{common ratio}\\&#10;----------\\&#10;r=-\frac{1}{4}\\&#10;a_1=-4096\\&#10;n=6&#10;\end{cases}&#10;\\\\\\&#10;a_6=-4096\left( -\frac{1}{4} \right)^{6-1}\implies a_6=-4^6\left( -\frac{1}{4} \right)^5
4 0
2 years ago
Read 2 more answers
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katrin2010 [14]
To find the answer, you must find the midpoint of their x-coordinates and their y-coordinates. To do that, you take the average between their x and y-coordinates.
So, in this case, it is:
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So, the answer is: (12,2)
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3 years ago
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Answer:

Harper can buy two bags of fruit with one box of crackers, she will have two dollars remaining.

Step-by-step explanation:

7 0
2 years ago
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