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Shkiper50 [21]
3 years ago
6

A hardware store rent vacuum cleaners that customers for part or all of A day before returning. The Store charges a flat fee Plu

s an hourly rate. Write a linear function F for the total retail cost of a vacuum cleaner.
Mathematics
1 answer:
Pavel [41]3 years ago
8 0

Answer:

Step-by-step explanation:

Let x represents the amount that the customer pays per hour

for renting the vacuum cleaner before returning it.

Let y represent the flat rate that the store charges a customer for renting the vacuum cleaner.

Let F represent the amount that the store charges a customer for renting the vacuum cleaner for x hours.

A linear function F for the total retail cost of a vacuum cleaner would be

F(x) = x + y

If the customer rents it for n hours, the total amount becomes

F(x) = nx + y

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(<br> x<br> −<br> 3<br> )<br> (<br> x<br> −<br> 1<br> )<br> (x−3)(x−1)
galina1969 [7]

Answer:

x² - 4x + 3

Step-by-step explanation:

When multiplying binomials (two terms in an expression), use FOIL. It stands for the first, outside, inside, and last terms in each bracket.

(x−3)(x−1)           Expand with FOIL

= x² - x - 3x + 3      Collect like terms

= x² - 4x + 3

7 0
3 years ago
Kristy is going to a college where tuition is $8,000 per year. She has a scholarship that pays 80% of tuition. Her aunt is givin
Nostrana [21]
8,000 x .80= 6,400
8,000-6,400= 1,600
1,600-1,000= 600 that is the amount of tuition she will need to pay each year.
3 0
3 years ago
Will give brainliest answer
natita [175]
A translation by 11 units to the left and 3 units up
4 0
3 years ago
Let event A = You buy a new pair of gloves on Saturday. Which event is most
Salsk061 [2.6K]

Answer:

C_ You finished a book on thursday.

Hope this helps

7 0
3 years ago
If a cup of coffee has temperature 97°C in a room where the ambient air temperature is 25°C, then, according to Newton's Law o
FinnZ [79.3K]

Answer:

The  average temperature  is T_{a} = 81.95^oC

Step-by-step explanation:

From the question we are told that

    The temperature of the coffee after time t is   T(t) =  25 + 72 e^{[-\frac{t}{45} ]}

Now the average temperature during the first 22 minutes i.e fro 0 \to  22minutes is mathematically evaluated as

              T_{a} =  \frac{1}{22-0}  \int\limits^{22}_{0} {25 +72 e^{[-\frac{t}{45} ]}} \, dx

               T_{a} = \frac{1}{22} [25 t  +  72 [\frac{e^{[-\frac{t}{45} ]}}{-\frac{1}{45} } ] ] \left| 22} \atop {0}} \right.

             T_{a} = \frac{1}{22} [25 t  - 3240e^{[-\frac{t}{45} ]} ] \left | 45} \atop {{0}} \right.

              T_{a} = \frac{1}{22} [25 (22)  - 3240e^{[-\frac{22}{45} ]}   - (- 3240e^{0} )]

            T_{a} = \frac{1}{22} [550  - 1987.12  +  3240]

          T_{a} = 81.95^oC

       

8 0
3 years ago
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