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3 years ago

Stephen gathered data about the average rainfall in two cities. He organized his data in the given graph.

Mathematics

2 answers:

skelet666 [1.2K]3 years ago

6 0

Answer:

b and e

Step-by-step explanation:

i took the test

Stels [109]3 years ago

4 0

Answer: B.The range Is Higher for city A than City B

E. The median is the same for city A and City B

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Evaluate 6² + (3.4) – 24

adell [148]

Answer:

=15.4

Step-by-step explanation:

6^2+(3.4)-24 = 36+3.4−24

36+3.4−24

39.4−24

=15.4

5 0

3 years ago

For the expression b^2-4by/2y^2-by-4y/b-2y. simplify the expression

Cloud [144]

Answer:

−2by^3 + b^2 − by − 4y/b − 2y

hope this helps! plz mark brainliest? :)

6 0

3 years ago

Is the relationship between 7s in 7,742 ant the 7s in 7,785 different in anyway? Explain

melisa1 [442]

The relationship between the 7's is not different in any way because the sevens are all in the same place. The sevens are in the hundreds and thousands place.

4 0

3 years ago

Please answer for 15 points Thank you

DedPeter [7]

Answer:3

Step-by-step explanation:

The answer is 3 because we know were adding

5 0

3 years ago

Read 2 more answers

In a box there are six envelopes each containing two cards. Three of the envelopes contain two red cards, two of them contain a

Sphinxa [80]

Answer:

$\frac{2}{5}$

Step-by-step explanation:

3 envelopes having 2 red card

2 envelopes having 1 red card and 1 black card

1 envelope having 2 black cards

We are given that . An envelope is selected at random and a card is withdrawn and found to be red.

So, No. of ways of envelope having red card = 3+2 = 5

No. of required ways of envelope having 1 red card and 1 black card = 2

So, probability of getting an envelope having 1 red card and 1 black card = $\frac{2}{5}$

Hence The chance the other card is black is $\frac{2}{5}$

5 0

3 years ago