<h3><em>(8)2+(x)2=(10)2</em></h3><h3><em>64+x2=100</em></h3><h3><em>x2=100-64</em></h3><h3><em>x2=36</em></h3><h3><em>x=6</em></h3><h3><em>BE = 6</em></h3><h3><em>hope it helps..stay blessed...thank you....</em></h3>

4 0

3 years ago

PLEASE ANSWER + BRAINLIEST!!<br><br> Factor completely.<br><br> 4k - 20k^9 =<br><br> 3b^2 - 108 =

Neporo4naja [7]

$4k-20k^9=4k(1-5k^8)=4k\left[1^2-(k^4\sqrt5)^2\right]\\\\=4k(1-k^4\sqrt5)(1+k^4\sqrt5)=4k\left[1^2-(k^2\sqrt[4]5)^2\right](1+k^4\sqrt5)\\\\=4k(1-k^2\sqrt[4]5)(1+k^2\sqrt[4]5)(1+k^4\sqrt5)\\\\=4k\left[1^2-(k\sqrt[8]5)^2\right](1+k^2\sqrt[4]5)(1+k^4\sqrt5)\\\\=4k(1-k\sqrt[8]5)(1+k\sqrt[8]5)(1+k^2\sqrt[4]5)(1+k^4\sqrt5)$

$3b^2-108=3(b^2-36)=3(b^2-6^2)=3(b-6)(b+6)$

$Used:\ (a-b)(a+b)=a^2-b^2$

7 0

3 years ago

The sum of the areas of the two circles is 80 pi square meters. Find the length of a radius of each circle of one of them is twi

nikklg [1K]

The radius of both circles are 4m and 8m.

7 0

3 years ago

Which of the following functions is graphed below?

balandron [24]

Answer:A

Step-by-step explanation:

7 0

3 years ago