Which expressions can you use to find 75% of 56? CHECK ALL THAT APPLY
1 answer:
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Answer:
1. The chi-squared statistic = 10.36
The degrees of freedom = 17
The p-value for the test = 0.89
2. The range of the p-value from the Chi squared table = 0.75 < p-value < 0.90
Step-by-step explanation:
1. The Chi squared test is given as follows;
Therefore,
UTI No UTI % Total
Cranberry juice 8 42 84 50
Lactobacillus 19 30 61 49
Control 18 30 60 50
The chi-squared statistic is given as follows;
The chi-squared statistic = 10.36
The degrees of freedom, df = 18 - 1 = 17 since the all of the expected count have a minimum value of 18
With the aid of the calculator we find the p value as p as follows;
The p-value for the test = 0.89
2. The range of the p-value from the Chi squared table is given as follows;
0.75 < p-value < 0.90.
How much pain would you find? hopefully none, since you'd have lots of pens and pencils :).
Answer:
(f/g)(x) = x³ - 7x + 2
(f/g)(2) = -4
Step-by-step explanation:
To find (f/g)(x), divide f(x) by g(x). The process is shown in the attached image.
(f/g)(x) = x³ - 7x + 2
To find (f/g)(2), plug in 2 wherever there is an x.
(f/g)(x) = x³ - 7x + 2
(f/g)(2) = (2)³ - 7(2) + 2
(f/g)(2) = 8 - 14 + 2
(f/g)(2) = -6 + 2
(f/g)(2) = -4
