3 years ago

ASAPPP SOMEONE PLEASEEE

Mathematics

1 answer:

Digiron [165]3 years ago

8 0

One is x = 1, the other is x = 0.

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PLEASE HELP- (-2, -7) (7, 2) (2, 7) (7, -2)

choli [55]

A=(7,3) b=(7,-2) c=(1,-2)

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2 years ago

How many zeroes are in the product of 40 x 107?

N76 [4]

Answer:

There's one 0.

Step-by-step explanation:

Because I multiplied it and there's only one 0.

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2 years ago

Read 2 more answers

Assume that the radius r of a sphere is expanding at a rate of 40 cm/min. The volume of a sphere is V = 4 3 πr3 and its surface

Scrat [10]

Answer:

The rate of change in surface area when r = 20 cm is 20,106.19 cm²/min.

Step-by-step explanation:

The area of a sphere is given by the following formula:

$A = 4\pi r^{2}$

In which A is the area, measured in cm², and r is the radius, measured in cm.

Assume that the radius r of a sphere is expanding at a rate of 40 cm/min.

This means that $\frac{dr}{dt} = 40$

Determine the rate of change in surface area when r = 20 cm.

This is $\frac{dA}{dt}$ when $r = 20$ . So

$A = 4\pi r^{2}$

Applying implicit differentiation.

We have two variables, A and r, so:

$\frac{dA}{dt} = 8r\pi \frac{dr}{dt}$

$\frac{dA}{dt} = 8*20\pi*40$

$\frac{dA}{dt} = 20106.19$

The rate of change in surface area when r = 20 cm is 20,106.19 cm²/min.

6 0

3 years ago

PLEASE HELP ME ASAPP HELP

Romashka [77]

Number one ☝️ right maybe

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3 years ago

A cylinder and its dimensions are diameter 8.4 cm and height 10.9 cm. Which measurement is closest to the lateral surface area o

Vanyuwa [196]

Answer:

287.64

Step-by-step explanation:

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3 years ago