First we need to determine what the 6 angles must add to. Turns out we use this formula
S = 180(n-2)
where S is the sum of the angles (result of adding them all up) and n is the number of sides. In this case, n = 6. So let's plug that in to get
S = 180(n-2)
S = 180(6-2)
S = 180(4)
S = 720
The six angles, whatever they are individually, add to 720 degrees. The six angles are y, y, 2y-20, 2y-20, 2y-20, 2y-20, <span>
They add up and must be equal to 720, so let's set up the equation to get...
(y)+(y)+(</span>2y-20)+(2y-20)+(2y-20)+(<span>2y-20) = 720
Let's solve for y
</span>y+y+2y-20+2y-20+2y-20+2y-20 = 720
10y-80 = 720
10y-80+80 = 720+80
<span>10y = 800
</span>
10y/10 = 800/10
y = 80
Now that we know the value of y, we can figure out the six angles
angle1 = y = 80 degrees
<span>angle2 = y = 80 degrees
</span><span>angle3 = 2y-20 = 2*80-20 = 140 degrees
</span>angle4 = 2y-20 = 2*80-20 =<span> 140 degrees
</span><span>angle5 = 2y-20 = 2*80-20 = 140 degrees
</span>angle6 = 2y-20 = 2*80-20 =<span> 140 degrees
</span>
and that's all there is to it
Answer:
2, 0, 2, 3, 5
1, 2, 4, 0, 5
Step-by-step explanation:
(ax + b)(cx² + dx + e)
acx³ + adx² + aex + bcx² + bdx + be
2(2)x³ + 2(3)x² + 2(5)x + 0 + 0 + 0
4x³ + 6x² + 10x
a = 2
b = 0
c = 2
d = 3
e = 5
1(4)x³ + 1(0)x² + 1(10)x + 2(4)x² + 0 + 10
4x³ + 8x² + 10x + 10
a = 1
b = 2
c = 4
d = 0
e = 5
No they do not form a right triangle
A, B and E.
Adding and multiplying the terms allow them to keep working. However, you must make sure that each variable is changed each time. Not just one as in C and D.
