we use equation 1 first.
-2x -y = -9
-y = -9 + 2x
y = 9 -2x
We substitute value of y in equation 2
5x - 2 (9 - 2x) = -9
5x -18 - 4x = -9
5x - 4x = -9 + 18
x = 18 -9
x = 9
We now find the value of y
-2x -y = -9
-2 (9) - y = -9
-18 - y = -9
-y = -9 + 18
y = 9 - 18
y = -9
The number of pounds that Billy's dog and Ruth's dog weigh in all is; 40 pounds
<h3>Algebra Word Problems</h3>
Weight of billy's dog = 30 pounds
Weight of Ruth's dog = 2/6 of billy's dog = 2/6 * 30 = 10 pounds
Thus, total weight of both billy and ruth's dog is;
Total weight = 30 + 10
Total weight = 40
Read more about Algebra Word Problems at; brainly.com/question/13818690
Let the two numbers be represented by x and y respectively.
Then x + y = 23, and x - y = 5.
Solve this system of linear equations for x and y. Start by rearranging them vertically:
x + y = 23
x - y = 5
--------------- Combining the two equations eliminates y:
2x = 28.
Then x = 14. If x = 14, then 14 + y = 23, and y = 9..
The solution is (14, 9); that is, x = 14 and y = 9.
4 = (-8) + 3x
Firstly, you can rearrange the equation to make it easier to read:
3x - 8 = 4
Add 8 on both sides to isolate the x:
3x = 12
Divide both sides by 3:
x = 4
Answer:
320 cups of soup
Step-by-step explanation:
Given;
Total number of guests expected T = 800
Proportion of that may order soup p = 2 out of 5 = 2/5
The number of cups he should prepare should be equal to the number of guests that are expected to order soup appetizer.
Number of guests Expected to order soup appetizer n is;
n = proportion × total guest = p × T
Substituting the given values;
n = 2/5 × 800 = 320
Therefore, he should prepare 320 cups of soup.
