All categories

2 years ago

Which of the following is the inverse of y=6^x? y=log_(6)x, y=log_(x)6, y=log_((1)/(6))x, y=log_(6)6x

Mathematics

2 answers:

Brums [2.3K]2 years ago

7 0

The answer is A, y=log_6 x.

kolezko [41]2 years ago

4 0

Answer:

y=log_(6)x

Step-by-step explanation:

From the definition of logarithm:

$x = log_b y$ <---> $y=b^x$

In our case, we have

$y=6^x$

which means that b=6, therefore the inverse function is

$x=log_6 y$

which can be rewritten by switching x and y:

$y=log_6 x$

You might be interested in

What is the function

Ede4ka [16]

The graph shows us that the slope of f(x) is -2. Now we gotta find the slope of g(x) to compare it to that of f(x). The equation of g(x) is in slope-intercept form (y = mx + b, where m is the slope and b is the y-intercept), so the slope is given to us for that one as well: it's -6. A line with a slope of -6 will be steeper than a line with a slope of -3, therefore the answer is B - the slope of f(x) is less than the slope of g(x).
Hope this helps.

3 0

3 years ago

Solve the equation for y<br><br> 6y+x=8

Igoryamba

Answer:

y=4/3-1/6x

Step-by-step explanation:

1) subtract "x" from both sides:

6y=8-x

2)divide by 6 on both sides(EVERYTHING WILL BE DIVIDED BY 6)

6y/6=(8-x)/6

y=(8-x)/6

2)simplify:

y=4/3-x/6

3 0

3 years ago

Read 2 more answers

(x3 - 2x² - 1) + (x - 1)

SSSSS [86.1K]

Answer:

x^3 -2x^2 -1 + (x-1)

= x^3 -2x^2 + x -2

= (x-2)(x^2+1)

Hope this helps!

5 0

2 years ago

Is this correct?<br> (im checking my answers)

zzz [600]

$1L=1,000mL\to1mL=\dfrac{1}{1,000}L=0.001L\\\\0.743mL=0.743(0.001L)=0.000743L\\\\Answer:\ \boxed{0.000743}$

6 0

3 years ago

Please help whoever answers this correctly I'll mark your answer brainliest

Oksana_A [137]

Answers:

Incorrect
Correct
Correct

==================================================

Explanation:

When applying any kind of reflections, the parallel sides will stay parallel. Check out the diagram below for an example of this.

So PQ stays parallel to RS. Also, QR stays parallel to PS.

The statement "PQ is parallel to PS" is incorrect because the two segments intersect at point P. This letter "P" is found in "PQ" and "PS" to show the common point of intersection. Parallel lines never intersect.

4 0

2 years ago