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3 years ago

6

Hiroto’s texting plan costs $20 per month, plus $0.05 per text message that is sent or received. Emilia’s plan costs $10 per mon

th and $0.25 per text. Using the graph below, which statement is true?
Hiroto’s plan costs more than Emilia’s plan when more than 50 texts are sent.
Both plans cost the same when 22 texts are sent.
Emilia’s plan costs more than Hiroto’s plan when more than 22 texts are sent.
Both plans cost the same when 50 texts are sent.

1 answer:

balu736 [363]3 years ago

5 0

Answer:

it's D

Step-by-step explanation:

y= .05x+20

x=50

y=.05(50)+20

2.5+20

y=22.5

y=.25x+10

x=50

y=.25(50)+10

12.5+10

y=22.5

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8x(5+7). please answer will give 10 pts & brainiest

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Answer:

96

Step-by-step explanation:

8x(5+7)

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3 years ago

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Some transportation experts claim that it is the variability of speeds, rather than the level of speeds, that is a critical fact

scZoUnD [109]

Answer:

Explained below.

Step-by-step explanation:

The claim made by an expert is that driving conditions are dangerous if the variance of speeds exceeds 75 (mph)².

(1)

The hypothesis for both the test can be defined as:

<em>H</em>₀: The variance of speeds does not exceeds 75 (mph)², i.e. <em>σ</em>² ≤ 75.

<em>Hₐ</em>: The variance of speeds exceeds 75 (mph)², i.e. <em>σ</em>² > 75.

(2)

A Chi-square test will be used to perform the test.

The significance level of the test is, <em>α</em> = 0.05.

The degrees of freedom of the test is,

df = n - 1 = 55 - 1 = 54

Compute the critical value as follows:

$\chi^{2}_{\alpha, (n-1)}=\chi^{2}_{0.05, 54}=72.153$

Decision rule:

If the test statistic value is more than the critical value then the null hypothesis will be rejected and vice-versa.

(3)

Compute the test statistic as follows:

$\chi^{2}=\frac{(n-1)\times s^{2}}{\sigma^{2}}$

$=\frac{(55-1)\times 94.7}{75}\\\\=68.184$

The test statistic value is, 68.184.

Decision:

$cal.\chi^{2}=68.184$

The null hypothesis will not be rejected at 5% level of significance.

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3 years ago

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3 years ago

Rectangles J and K are similar. If the area of rectangle J is 440, what is the area of rectangle K? I need this today

Hunter-Best [27]

Answer:

$Area = 27.5$

Step-by-step explanation:

Given

$J_{Area} = 440$

$J_{Width} = 22$

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<em>See attachment</em>

Required

Determine the area of K

First, we need to calculate the length of the rectangle J

$J_{Length} * J_{Width} = J_{Area}$

This gives:

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Divide both sides by 22

$\frac{J_{Length} * 22}{22} = \frac{440}{22}$

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So, the length of the rectangle J is 20.

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$J_{Length} : J_{Width} = K_{Length} : `K_{Width}$

Substitute the known values:

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Express as fraction:

$\frac{20 }{ 22 }= \frac{K_{Length} }{ `5.5}$

Make Length, the subject of formula

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$K_{Length} = \frac{110}{22}$

$K_{Length} = 5$

The area of K is:

$Area = K_{Length} * K_{Width$

$Area = 5.5 * 5$

$Area = 27.5$

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3 years ago