Answer:
I. First number, a = 40.
II. Second number, b = 50.
III. Third number, c = 120.
Step-by-step explanation:
Let the three numbers be a, b and c respectively.
Given the following data;
Translating the word problem into an algebraic equation, we have;
a + b + c = 210
b = a + 10
c = 3a
Substituting the value of b and c into the equation, we have;
a + a + 10 + 3a = 210
5a + 10 = 210
5a = 210 - 10
5a = 200
a = 200/5
<em>a = 40</em>
To find the value of b;
b = a + 10
b = 40 + 10
<em>b = 50</em>
To find c
c = 3a
c = 3*40
<em>c = 120</em>
Keep multiplying the number by 31, and write that down to show ur work
Answer:
what are you learning
Step-by-step explanation:
Since the compiler reads top down, it should print “yesno” because they are both true
Answer:
Step-by-step explanation:
y = -12x - 1
y = 14x - 4
-12x - 1 = 14x - 4
-1 + 4 = 14x + 12x
3 = 26x
3/26 = x
y = 14x - 4
y = 14(3/26) - 4
y = 42/26 - 4
y = 42/26 - 104/26
y = - 62/26 reduces to - 31/13
solution : x = 3/26 and y = -31/13 or (3/26,-31/13)