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Stella [2.4K]
3 years ago
8

Find the sum 2 2/3 + 2 2/3

Mathematics
1 answer:
Len [333]3 years ago
5 0

Answer: 5 and 1/3

Step-by-step explanation: To add mixed numbers, first add the fractions.

So here, we have 2/3 + 2/3 which is 4/3.

Then add the whole numbers.

So we have 2 + 2 which is 4.

So our answer is 4 and 4/3.

But notice, that since 4/3 is an improper fraction, or answer is not in lowest terms. 4/3 can be rewritten as the mixed number 1 and 1/3. So 4 and 4/3 is the same as 4 + 1 and 1/3 which is 5 and 1/3.

Since 5 and 1/3 is in lowest terms, this is our final answer.

So we can say that 2 and 2/3 + 2 and 2/3 is 5 and 1/3

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How long would it take a giant tortoise to travel 5 meters if it can travel 1/10 meter per second?
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The number of vehicles passing through a bank drive -up line during each 15-minute period was recorded. The results are shown be
tangare [24]

Answer:

Step-by-step explanation:

I think the median you are asking is the middle value,

because there is a total of 20 vehicles,  there are two middle number: 31 and 31.

To solve this:

you first plus these two numbers together, you will get 62.

then divide them by 2, then you will get the middle number.

the middle number will be 31. ( actually because theese two number are the same, you do not really need to plus them then divide by 2, you could just answer the question 31, but because when you do other question and has the same situation but not the same number, (suppose you got 20 and 21) Then you need to do this question like I said above)

I wish this could help you.

8 0
3 years ago
Find the value of 1×4+2×5+3×6......n×(n+3)​
Arada [10]

Answer:

n(n+1)(n+5)/3

Step-by-step explanation:

there is no value, as we don't know n.

but we can create a summary formula/ function definition :

this is the sum for k = 1 to n of k×(k+3)

k×(k+3) = k² + 3k

so, the overall sum splits into the sum of k² for k=1 to n, and the sum of 3k for k=1 to n.

and the sum of 3k is 3 times the sum of k for k=1 to n.

Σk² for k=1 to n = [n(n+1)(2n+1)]/6

Σk for k=1 to n = n(n+1)/2

3×Σk for k=1 to n = 3×n(n+1)/2

so, we have a function formula

n(n+1)(2n+1)/6 + 3n(n+1)/2 = n(n+1)(2n+1)/6 + 9n(n+1)/6 =

= n(n+1)(2n+1+9)/6 = n(n+1)(2n+10)/6 = n(n+1)(n+5)/3

3 0
3 years ago
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