Answer:
The 2nd number in the sequence is
Step-by-step explanation:
Let the six even numbers be 2x,2x+2,2x+4,2x+6,2x+8,2x+10
We are given that The sum of 6 even integers is 130.
So,2x+2x+2+2x+4+2x+6+2x+8+2x+10=130
12x+30=130
12x=100
So,the 2nd number in the sequence is
Answer:
Part (A): There are 9 integers between 5 and 31 which are divisible by 3.
Part (B): There are 6 integers between 5 and 31 which are divisible by 4.
Part (C): There are 2 integers between 5 and 31 which are divisible by 3 and by 4.
Step-by-step explanation:
Consider the provided information.
Part (A) we need to find how many integers between 5 and 31 are divisible by 3.
Between 5 and 31 there are 25 integers.
According to quotient rule:
That means either 8 or 9 integers are divisible by 3 as 8.33 lies between 8 and 9.
The integers are: 6, 9, 12, 15, 18, 21, 24, 27, 30
Hence, there are 9 integers between 5 and 31 which are divisible by 3.
Part (B) we need to find how many integers between 5 and 31 are divisible by 4.
Between 5 and 31 there are 25 integers.
According to quotient rule:
That means either 6 or 7 integers are divisible by 4, as 6.25 lies between 6 and 7.
The integers are: 8, 12, 16, 20, 24, 28
Hence, there are 6 integers between 5 and 31 which are divisible by 4.
Part (C) we need to find how many integers between 5 and 31 are divisible by 3 and by 4
Between 5 and 31 there are 25 integers.
Integers should be divisible by 3 and by 4, that means integers should be divisible by 3×4=12.
According to quotient rule:
That means either 2 or 3 integers are divisible by 3 and by 4 or 12, as 2.08 lies between 2 and 3.
The integers are: 12, 24,
Hence, there are 2 integers between 5 and 31 which are divisible by 3 and by 4.