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Valentin [98]
2 years ago
10

Plssss helppppppppppp

Mathematics
2 answers:
navik [9.2K]2 years ago
5 0

Answer:

The quotient of x and 3

Hope this helps : )

Yuki888 [10]2 years ago
3 0

Answer:

Ok

Step-by-step explanation:

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PLEASE HELP ITS PI i really need help
11Alexandr11 [23.1K]

Answer:

2

Step-by-step explanation:

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2 years ago
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Please Help!!!!!!!!!!!!!!!!!!!!!<br> Will mark BRAINLIEST
Llana [10]

Answer:

○ \displaystyle -6m(m - 4)(m - 6)

Step-by-step explanation:

\displaystyle 6m^3 - 60m^2 + 144m \\ 6m[m^2 - 10m + 24m] \\ \\ \boxed{6m[m - 4][m - 6]}

I am joyous to assist you at any time.

5 0
2 years ago
I need help again. once again due TM helppp
vekshin1
Since the object is a cube, times 42 three times by itself. You have to do this because it is length x width x height. 42 x 42 x 42. The answer you're looking for is 74,088 cubic inches because it is three-dimensional.
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2 years ago
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HELP!!! URGENT!!! I WILL GIVE BRAINLEIST THING ​
lisov135 [29]

Answer:

Horizontal distance = 0 m and 6 m

Step-by-step explanation:

Height of a rider in a roller coaster has been defined by the equation,

y = \frac{1}{3}x^{2}-2x+8

Here x = rider's horizontal distance from the start of the ride

i). y=\frac{1}{3}x^{2}-2x+8

      =\frac{1}{3}(x^{2}-6x+24)

      =\frac{1}{3}[x^{2}-2(3x)+9-9+24]

      =\frac{1}{3}[(x^{2}-2(3x)+9)+15]

      =\frac{1}{3}[(x-3)^2+15]

      =\frac{1}{3}(x-3)^2+5

ii). Since, the parabolic graph for the given equation opens upwards,

    Vertex of the parabola will be the lowest point of the rider on the roller coaster.

    From the equation,

    Vertex → (3, 5)

    Therefore, minimum height of the rider will be the y-coordinate of the vertex.

    Minimum height of the rider = 5 m

iii). If h = 8 m,

    8=\frac{1}{3}(x-3)^2+5

    3=\frac{1}{3}(x-3)^2

    (x - 3)² = 9

    x = 3 ± 3

    x = 0, 6 m

    Therefore, at 8 m height of the roller coaster, horizontal distance of the rider will be x = 0 and 6 m

6 0
2 years ago
First, and correct answer gets brainliest, also worth 50 points
pishuonlain [190]

One angle be x

  • other is 2x-6

ATQ

\\ \sf\longmapsto x+2x-6=90

\\ \sf\longmapsto 3x-6=90

\\ \sf\longmapsto 3x=96

\\ \sf\longmapsto x=32

\\ \sf\longmapsto 2x-6=2(32)-6=58°

4 0
2 years ago
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