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3 years ago

How do you do this?

2 answers:

6 0

So the trickiest part about these is finding how to get the middle term. The easiest way to do this is by multiplying your end terms, 3 and -8, and using the factors to find how to get the middle term:

3 x -8 = -24
Factors of 24 = 1,2,3,4,6,8,12,24

Now we need two of these factors to add to make +10, in this case it'd be 2 and 12. The reason this works is because our number is -24, so one of the factors is going to be negative, in this case we make the 2 negative: -2+12=10

Now we set up the equation like so:

3x^2 + 12x -2x - 8

Now simplify by pulling out common terms:

3x(x+4) - 2(x+4)
(3x-2)(x+4)

Ta-da, your polynomial is now 2 binomials

It takes lots of practice, but once you get the hang of it they get easier to do in your head. Keep at it!

Sholpan [36]3 years ago

4 0

put the first equation in the graphic calculator in y= #1 then in y=#2 put one of the answer choices, if the y1 & y2 match that will be your answer

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16. Jerome is a co-owner of a small company and received 1/3 of the company’s profits this year. What were the company’s overall

AlekseyPX

Remark
The trick to this question is realizing what you took 1/3 of. Did you take it of the 150000 or is it 1/3 of some total you have to find. I don't think you could come up with a third choice.

It turns out that the answer is 1/3 of a number you don't know.

Equation
(1/3) x = 150000 Multiply both sides by 3
3*(1/3) x = 150000 * 3
x = 150000 * 3
x = 450000

Conclusion
The amount the company makes is 450000 dollars / year.

6 0

3 years ago

A triangle ABC has its vertices at A(-2, -3), B(2, 1), and C(5,-1).

maksim [4K]

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill ~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-3})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{1}) ~\hfill AB=\sqrt{( 2- (-2))^2 + ( 1- (-3))^2} \\\\\\ AB=\sqrt{(2+2)^2+(1+3)^2}\implies AB=\sqrt{32}\implies \boxed{AB=4\sqrt{2}} \\\\[-0.35em] ~\dotfill$

$B(\stackrel{x_1}{2}~,~\stackrel{y_1}{1})\qquad C(\stackrel{x_2}{5}~,~\stackrel{y_2}{-1}) ~\hfill BC=\sqrt{( 5- 2)^2 + ( -1- 1)^2} \\\\\\ BC=\sqrt{3^2+(-2)^2}\implies BC=\sqrt{9+4}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{5}~,~\stackrel{y_1}{-1})\qquad A(\stackrel{x_2}{-2}~,~\stackrel{y_2}{-3}) ~\hfill CA=\sqrt{( -2- 5)^2 + ( -3- (-1))^2} \\\\\\ CA=\sqrt{(-7)^2+(-3+1)^2}\implies CA=\sqrt{49+(-2)^2}\implies \boxed{CA=\sqrt{53}}$

$\stackrel{\textit{\large perimeter of ABC}}{4\sqrt{2}+\sqrt{13}+\sqrt{53}~~\approx~~ 16.54}$

3 0

2 years ago

What is the difference of 5 and 2/5? Show your work.

tatuchka [14]

Answer:

This is the answer, let me know if something isn't clear

3 0

3 years ago

HELPPP!!!

madam [21]

Answer:

2 and a half @ 2.5 inches (sorry i can't type the fraction)

Step-by-step explanation:

english is my second language so sorry if you doesn't understand:

(1/2, 1/4)=(x,y)

based on the graph shown that each grid on the y axis represents 1/4, that is the smallest scale stood in the y axis.

this means 2 grid= 1/4 x 2 = 1/2 @ 0.5 inches.

since the '5 months-hair-length' is above about 2 grid above 2 inch:

2 inch + 0.5 inch= 2.5 inch

4 0

3 years ago

Every quadrilateral with opposite angles supplementary can be inscribed in a circle.TrueFalseIf a triangle is inscribed in a cir

solniwko [45]

Explanation

The Inscribed Quadrilateral Theorem states that a quadrilateral can be inscribed in a circle if and only if the opposite angles of the quadrilateral are supplementary

Answer 1: True

Also, Given a triangle, the circumscribed circle is the circle that passes through all three vertices of the triangle. The center of the circumscribed circle is the circumcenter of the triangle, the point where the perpendicular bisectors of the sides meet.

Answer 2: True

7 0

1 year ago