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3 years ago

Show that each statement is true: Cos^4X-sin^4X=2cos^2X-1

1 answer:

Ivan3 years ago

4 0

$cox^4x-sin^4x=2cos^2x-1\\\\
(cosx^2-sin^2x)(cosx^2x+sin^2x)=2cos^2x-1\\\\
cosx^2-sin^2x*1=2cos^2x-1\ \ \ | subtract\ 2cos^2x\\\\
-cosx^2-sin^2x=-1\ \ \ | multiply\ by\ -1\\\\
cosx^2+sin^2x=1\\\\
1=1$

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IRINA_888 [86]

Answer:

Drink A

Step-by-step explanation:

Let's find the amount of sugar in each drink in every 35 ounces. (since 35 is the lowest common multiple of 5 and 7)

Drink A

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2 years ago

The base of a solid in the region bounded by the two parabolas y2 = 8x and x2 = 8y. Cross sections of the solid perpendicular to

Usimov [2.4K]

The two curves intersect at two points, (0, 0) and (8, 8):

$x^2=8y\implies y=\dfrac{x^2}8$

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The area of a semicircle with diameter $d$ is $\dfrac{\pi d^2}8$ . The diameter of each cross-section is determined by the vertical distance between the two curves for any given value of $x$ between 0 and 8. Over this interval, $y^2=8x\implies y=\sqrt{8x}$ and $\sqrt{8x}>\dfrac{x^2}8$ , so the volume of this solid is given by the integral

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3 years ago

PLEASE HELP IF YOU ARE NOT SURE DON'T Answer PLEASE SHOW WORK AND STEPS

Vaselesa [24]

X is less than 4.
Just simplify each side and solve for the variable.
First add 9 to both sides.
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3 years ago

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kupik [55]

Answer:

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Step-by-step explanation:

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2 years ago

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Evgen [1.6K]

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Step-by-step explanation:

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