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Stels [109]
3 years ago
11

PLEASE ANSWER QUICKLY

Mathematics
2 answers:
statuscvo [17]3 years ago
8 0
If we assume the two smaller triangles in the larger triangle are similar because they share a side, then p=27. 

29-11=18 would give us the value for the lower side of the rightmost triangle. Then was can use a ratio to compare the outer sides of both inner triangles.

16.5/11 = x/18
x=27
Luba_88 [7]3 years ago
6 0
29-11=18
18²+18²=p²
324+324=p²
p²=648
p=18√2
That's your answer.
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1 4/8 in a improper fraction?
stiv31 [10]
<h2>Answer:\frac{3}{2}<u><em></em></u></h2>

Step-by-step explanation:

Step 1: Multiply the whole number part (1) by the denominator (8).

1 × 8 = 8

Step 2: Add the product from Step 1 (8) to the numerator (4).

8 + 4 = 12

Step 3: Write that result (12) above the denominator. So,

\frac4{8}{1}

Step 4: The fraction \frac{12}{8}

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\frac1{4}{8} =\frac{3}{2}

8 0
2 years ago
A drawer contains 2 red shirts and 4 blue shirts. A second drawer contains 3 pairs of grey pants and 2 pairs of blue pants. A th
viktelen [127]

Answer:

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2 years ago
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Ilya [14]

Given:

The vertices of the rectangle ABCD are A(0,1), B(2,4), C(6,0), D(4,-3).

To find:

The area of the rectangle.

Solution:

Distance formula:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using the distance formula, we get

AB=\sqrt{(2-0)^2+(4-1)^2}

AB=\sqrt{(2)^2+(3)^2}

AB=\sqrt{4+9}

AB=\sqrt{13}

Similarly,

BC=\sqrt{(6-2)^2+(0-4)^2}

BC=\sqrt{(4)^2+(-4)^2}

BC=\sqrt{16+16}

BC=\sqrt{32}

BC=4\sqrt{2}

Now, the length of the rectangle is AB=\sqrt{13} and the width of the rectangle is BC=4\sqrt{2}. So, the area of the rectangle is:

A=length \times width

A=\sqrt{13}\times 4\sqrt{2}

A=4\sqrt{26}

A\approx 20

Therefore, the area of the rectangle is 20 square units.

3 0
2 years ago
When a number x is multiplied by 4, the result is 2/5. What is t he value of x
PIT_PIT [208]

The equation:

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3 years ago
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solniwko [45]
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