Tell whether the ordered pair is a solution to the given in equality (-2,1);y<-2x+7

Mathematics

1 answer:

Papessa [141]3 years ago

5 0

$\text{Plug in ordered pair into inequality and solve:}\\\\1$

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A group of tenth grade students responded to a survey that was asked which Math course they were currently enrolled in. The surv

ale4655 [162]

Answer:

Step-by-step explanation:

The bottom-right most cell tells us that the total number of students that responded to the survey is 310 students.

To find the answer, we can go through each choice.

A. Females taking Geometry

Row 1 Column 2 tells us that 53 females are taking geometry. 53/310 is about 17%.

B. Females taking Algebra II.

Row 1 Colume 3 tells us that 62 females are taking Algebra II. 62/310 is 20%.

C. Males taking Geometry.

Row 2 Colume 2 tells us that 59 males are taking Geometry. 59/310 is about 19%. Choice C is correct.

D. Males taking Algebra I.

44 out of the total 310 respondents are male and is taking Algebra I. 44/310 is about 14%.

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Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Csqrt%7B%20x%5E%7B2%7D-10x%2B25%7D%2B25%2B12%5Csqrt%7Bx%7D%20%3D15%5Csqrt%7Bx%7D" id="TexFor

vodomira [7]

Step-by-step explanation:

$\sqrt{ x^{2}-10x+25}+25+12\sqrt{x} =15\sqrt{x} \\ \\ \therefore \: \sqrt{ x^{2}-10x+ {5}^{2} }+25 =15\sqrt{x} - 12\sqrt{x}\\ \\ \therefore \: \sqrt{( x - 5)^{2}}+25 =3\sqrt{x} \\ \\ \therefore \: x - 5+ 25 = 3 \sqrt{x} \\ \\ \therefore \: x + 20 = 3 \sqrt{x} \\ \\ squaring \: both \: sides \\ (x + 20)^{2} = ( {3 \sqrt{x} })^{2} \\ \therefore \: {x}^{2} + 40x + 400 = 9x \\ \therefore \: {x}^{2} + 40x + 400 - 9x = 0 \\ \therefore \: {x}^{2} + 31x + 400 = 0 \\$