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Assoli18 [71]
3 years ago
12

What is the remainder of 10^2017 divided by 1001?

Mathematics
1 answer:
pashok25 [27]3 years ago
5 0
Note: When I use the double equal sign, I mean the triple bar used with modular arithmetic

10^3 = 1000 == -1 (mod 1001)
10^3 == -1 (mod 1001)
(10^3)^672 == (-1)^672 (mod 1001)
(10^(3*672) == 1 (mod 1001)
10^2016 == 1 (mod 1001)
10*10^2016 == 10*1 (mod 1001)
10^2017 == 10 (mod 1001)

Final Answer: 10


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Element X decays radioactively with a half life of 6 minutes. If there are 790 grams of Element X, how long, to the nearest tent
frosja888 [35]

Answer:

It takes 27 minutes for the element to decay to 35 grams

Step-by-step explanation:

Given:

Initial amount  =  790 grams

Final amount =  35 grams

Half life =  6 minutes

To find:

Time taken for the element to reduce into 35 grams  = ?

Solutions

Time taken = half life  \times \frac{ log(\frac{ initial amount}{final amount})}{log(2)}

On substituting the values given, Time taken  

= 6 \times \frac{log(\frac{790}{35})}{log(2)}

= 6 \times \frac{log(22.57)}{log(2)}

= 6 \times 4.496

= 26.97

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3 years ago
Hillary needs to know if the triangle shown is a right triangle. Which equation should she use to help?
Sonja [21]

Answer:

a2+b2=c2

Step-by-step explanation:

A right triangle is a triangle in which one of the angles is a 90∘ angle. A triangle can be determined to be a right triangle if the side lengths are known. If the lengths satisfy the Pythagorean Theorem (a2+b2=c2) then it is a right triangle.

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The total number of​ restaurant-purchased meals that the average person will eat in a​ restaurant, in a​ car, or at home in a ye
zloy xaker [14]

Answer:

Number of​ restaurant-purchased meals eaten in a​ restaurant = 70

Number of​ restaurant-purchased meals eaten in a​ car = 22

Number of​ restaurant-purchased meals eaten in a​ home = 60

Step-by-step explanation:

Let the number of people that will eat in a restaurant be R.

Let the number of people that will eat in a car be C.

Let the number of people that will eat in a home be H.

From the information given in the problem we have,

R+C+H = 152 ____equation (1)

C+H-R = 12 ____equation (2)

R = H+10 ____equation (3)

1) Plugging in R=H+10 from equation 3 into the equation 2, we get

C+H-R=12

=> C+H-(H+10)=12

=> C+H-H-10=12

2) Cancelling out +H and -H, we get

C-10=12

3) Add 10 to both sides

C-10+10=12+10

4) Cancelling out -10 and +10, we get

C=22

5) Plugin C=22 in equation 1, we have

R+C+H = 152

=> R+22+H=152

Subtract 22 from both sides,

R+22+H-22=152-22

Cancelling out +22 and -22 from the left side, we get

R+H=130 ____let it be equation (4)

6) Plugin C=22 in equation 2, we have

C+H-R = 12

22+H-R = 12

Subtracting 22 from both the sides, we get

22+H-R-22 = 12-22

Cancelling out +22 and -22 from the left side,

H-R = -10 ____let it be equation (5)

7) Adding equation 4 and equation 5, we get

(R+H)+(H-R) = 130 + (-10)

=> R+H+H-R = 130-10

8) Cancelling out R and -R from the left side, we get

2H = 120

9) Dividing both sides by 2, we get

\frac{2H}{2} = \frac{120}{2}

10) Cancelling out the 2's from the left side, we have

H=60

11) Plugging in C=22 and H=60 in the equation 1, we have

R+C+H = 152

=> R+22+60=152

=> R + 82 = 152

12) Subtracting 82 from both the sides, we get

R + 82 -82 = 152 -82

13) Cancelling out +82 and -82 from the left side, we get

R = 70

<em>So, C=22, H=60, R=70</em>

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Answer:

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