Answer:
The prove is as given below
Step-by-step explanation:
Suppose there are only finitely many primes of the form 4k + 3, say {p1, . . . , pk}. Let P denote their product.
Suppose k is even. Then P ≅ 3^k (mod 4) = 9^k/2 (mod 4) = 1 (mod 4).
ThenP + 2 ≅3 (mod 4), has to have a prime factor of the form 4k + 3. But pₓ≠P + 2 for all 1 ≤ i ≤ k as pₓ| P and pₓ≠2. This is a contradiction.
Suppose k is odd. Then P ≅ 3^k (mod 4) = 9^k/2 (mod 4) = 1 (mod 4).
Then P + 4 ≅3 (mod 4), has to have a prime factor of the form 4k + 3. But pₓ≠P + 4 for all 1 ≤ i ≤ k as pₓ| P and pₓ≠4. This is a contradiction.
So this indicates that there are infinite prime numbers of the form 4k+3.
Answer:
I think the F could mean force like F = ma (mass acceleration)
Step-by-step explanation:
The two rational numbers between
and
is
,
<h3>How to find the rational numbers between -3/4 and -2/3?</h3>
In the form of p/q, which can be any integer and where q is not equal to 0, is expressed as rational numbers. As a result, rational numbers also contain decimals, whole numbers, integers, and fractions of integers (terminating decimals and recurring decimals).
given that -3/4 and -2/3
now take L.C.M between these two rational numbers is 12.
now multiply -3/4 with 3 both numerator and denominator

again multiply -9/12 with 4 both numerator and denominator

now multiply -2/3 with 4 both numerator and denominator

again multiply -8/12 with 4 both numerator and denominator

Hence the -36/48 and -32/48 are rational numbers between -3/4 and -2/3
Learn more about rational numbers, refer:
brainly.com/question/12088221
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