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2 years ago

Find slope for 2x+5y=8?

2 answers:

8 0

Get y by itself to be in slope-intercept form, which is: y=mx+b
m=slope
b=y-intercept
To do that subtract 2x from both sides to get: 5y=-2x+8. You're not done yet because y still isn't by itself so you divide both sides by five and you get: y= -2/5x+8/5
m= -2/5 which is the slope so the slope is equal to -2/5

Nitella [24]2 years ago

7 0

First thing, you need to transform this equation to the form of y = ax + b

So you get:
2x + 5y = 8
5y = -2x + 8
$y = -\frac{2}{5} x + \frac{8}{5}$

In the form of y = ax + b, a is the slope.
In $y = -\frac{2}{5} x + \frac{8}{5}$ , you can see " $- \frac{2}{5} x$ ", and always the number before x is the slope
So, the slope of 2x + 5y = 8 is $- \frac{2}{5}$

Hope this Helps :)

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Answer:

Step-by-step explanation:

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critical z factor = 2.58

Now we have the following formula:

ME = z * (sd / sqrt (N) ^ (1/2))

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6 = 2.58 * (14 / (N) ^ (1/2))

solving for N we have:

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

What is the slope-intercept form equation of the line that passes through (2, 4) and (4, 10)? (5 points) a y = −3x − 2 b y = −3x

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Step-by-step explanation:

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2 years ago

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Answer:

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Step-by-step explanation:

Given [Missing from the question]

Equation:

$cos\theta = \frac{\sqrt 3}{2}$

Interval:

$0 \le \theta \le 360$

$0 \le \theta \le 2\pi$

Required

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$cos\theta = \frac{\sqrt 3}{2}$

... shows that the value of $\theta$ is positive

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So, we have:

$cos\theta = \frac{\sqrt 3}{2}$

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2 years ago