Answer:
4/992 = 0.00403225806
Step-by-step explanation:
I hope this helps!!
Answer:
Step-by-step explanation:
Given that a basketball coach will select the members of a five-player team from among 9 players, including John and Peter.
Out of nine players five are chosen at random.
The team consists of John and Peter.
Hence we can sort 9 players as I group, John and Peter and II group 7 players.
Now the selection is 2 from I group and remaining 3 from II group.
Hence no of ways of selecting a team that includes both John and Peter=
=35
Total no of ways =
=126
=
=
Answer:
look below
Step-by-step explanation:
thing to note:
sin = opposite/hypotenuse
cos = adjacent/hypotenuse
tan = opposite/adjacent
opposite= side across angle you are using
hypotenuse= side across 90 degree angle
adjacent= remaining side
angle B
sin = 6/10
cos = 8/10
tan = 6/8
angle C
sin = 8/10
cos = 6/10
tan = 8/6
hope that helped. let me know if you have any questions:)