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irina1246 [14]
3 years ago
10

Identify the solution(s) of the system of equations, if any. -6x - 4y = 12 12y = -18x - 36

Mathematics
1 answer:
UkoKoshka [18]3 years ago
5 0
-6x - 4y = 12|\div 2\\
12y = -18x - 36|\div 6\\\\
-3x-2y=6\\
2y=-3x-6\\\\
-3x-2y=6\\
-3x-2y=6

Both equations are equivalent, so there are infinitely many solutions.
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To eliminate the y terms and solve for x in the fewest steps, by which constants should the equation need multiplied by before a
ivanzaharov [21]
A. Multiplied by 2 for the first then for the second multiply by three.

Explanation: the equations already have opposite signs for y so reversing the signs would be counterproductive. (Eliminates B and D) and the easiest way is to get the numbers before the Y variable to be the same. The top by 2 and bottom by 3 would do that, leaving only A.
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nadia needs to buy some cheddar cheese an 8-ounce package of cheddar cheese costs $2.40 a 12 -ounce package of cheddar cheese co
jeka57 [31]

Answer:

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Step-by-step explanation:

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3 years ago
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12(x-20)=-48 what is x
Sophie [7]

Answer:

x = 16

Step-by-step explanation:

12(x - 20) = -48

Use distributive property

12*x - 12*20 = -48

12x - 240 = -48

Add 240 to both sides

12x = -48 + 240

12x = 192

Divide both sides by 12

x = 192/12

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3 0
2 years ago
Graphing in Point-Slope Form y−y1=m(x−x1) <br> ​<br> Graph the equation y+7=−45(x−4) ?
nevsk [136]

Answer:

<h2>The graph is in the attachment.</h2>

Step-by-step explanation:

The point-slope form of an equation of a line:

y-y_1=m(x-x_1)

<em>m</em><em> - slope</em>

<em>(x₁, y₁)</em><em> - a point on a line</em>

The slope-intercept form of an equation of a line:

y=mx+b

<em>m</em><em> - slope</em>

<em>b</em><em> - y-intercept → (0, b)</em>

We have the equation in a point-slope form:

y+7=-\dfrac{4}{5}(x-4)

y-(-7)=-\dfrac{4}{5}(x-4)

Therefore we have one point: <em>(4, -7)</em><em>.</em>

<em>Convert to the slope-intercept form:</em>

y+7=-\dfrac{4}{5}(x-4)              <em>use the distributive property</em>

y+7=-\dfrac{4}{5}x+\left(-\dfrac{4}{5}\right)(-4)

y+7=-\dfrac{4}{5}x+\dfrac{16}{5}

y+7=-\dfrac{4}{5}x+3\dfrac{1}{5}          <em>subtract 7 from both sides</em>

y=-\dfrac{4}{5}x-3\dfrac{4}{5}

Put <em>x = -1</em><em> </em>to the equation:

y=-\dfrac{4}{5}(-1)-3\dfrac{4}{5}=\dfrac{4}{5}-3\dfrac{4}{5}=-3

Therefore we have the second point <em>(-1, -3)</em>.

3 0
3 years ago
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