Answer: Satisfied for n=1, n=k and n=k+1
Step-by-step explanation:
The induction procedure involves two steps
First is
Basic Step
Here we consider that for the value n=1, there is one car and it will always make the full circle.
Induction Step
Since basic step is satisfied for n=1
Now we do it for n=k+1
Now according to the statement a car makes full circle by taking gas from other cars as it passes them. This means there are cars that are there to provide fuel to the car. So we have a car that can be eliminated i.e. it gives it fuels to other car to make full circle so it is always there.
Now ,go through the statement again that the original car gets past the other car and take the gas from it to eliminate it. So now cars remain k instead of k+1 as it's fuel has been taken. Now the car that has taken the fuel can make the full circle. The gas is enough to make a circle now.
So by induction we can find a car that satisfies k+1 induction so for k number of cars, we can also find a car that makes a full circle.
You know a1.
So find a2, a3, and so on until a7.
a(1) = 12
a(2) = 16
a(3) = 20
a(4) = 24
a(5) = 28
a(6) = 32
a(7) = 36
Each is 4 more than the previous.
Answer:
Step-by-step explanation:
Simplifying
-3a + 8 = 2z + -12
Reorder the terms:
8 + -3a = 2z + -12
Reorder the terms:
8 + -3a = -12 + 2z
Solving
8 + -3a = -12 + 2z
Solving for variable 'a'.
Move all terms containing a to the left, all other terms to the right.
Add '-8' to each side of the equation.
8 + -8 + -3a = -12 + -8 + 2z
Combine like terms: 8 + -8 = 0
0 + -3a = -12 + -8 + 2z
-3a = -12 + -8 + 2z
Combine like terms: -12 + -8 = -20
-3a = -20 + 2z
Divide each side by '-3'.
a = 6.666666667 + -0.6666666667z
Simplifying
a = 6.666666667 + -0.6666666667z
Answer:
<u>Cost = 25 + 50h</u>
cost for 8 hours of work = $425
cost for 10 hours of work = $525
Step-by-step explanation:
The question is as following:
A plumber charges $25 for a service call plus $50 per hour of service write an equation to represent the cost of hiring this plumber.
what will be the cost for 8 hours of work? 10 hours of work?
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A plumber charges $25 for a service call plus $50 per hour
<u>Cost = 25 + 50h</u>
Where h is the number of hours of service
8 hours of work: h = 8
Substitute with h = 8 at the equation of cost
<u>Cost = 25 + 50* 8 = $425</u>
10 hours of work: h = 10
Substitute with h = 10 at the equation of cost
<u>Cost = 25 + 50 * 10 = $525</u>
