Graph the function y=x^2-4

An abstract sculpture in the form of a triangle has a base 21 meters and a height of 12 meters. Find the are of the triangle.

charle [14.2K]

The area of a triangle could be determined using the following formula
$\boxed{a= \frac{1}{2} \times b \times h}$

plug in the numbers
$a = \frac{1}{2} \times 21 \times 12$
$a = \frac{1}{2} \times 252$
$a= \frac{252}{2}$
a = 126

The area of the triangle is 126 square meters

8 0

2 years ago

A class consists of 23 women and 83 mean. If a student is random selected, what is the probability that the student is a woman?

slavikrds [6]

Answer:

$P(Woman) = \frac{23}{106}$

Step-by-step explanation:

Given

$Women = 23$

$Men = 83$

Required

$P(Woman)$

This is calculated as the number of women divided by the population of the class

i.e.

$P(Woman) = \frac{Women}{Women + Men}$

So, we have:

$P(Woman) = \frac{23}{23+83}$

$P(Woman) = \frac{23}{106}$

7 0

2 years ago

the line containing the altitude to the hypotenuse of a right triangle whose vertices are p(-1, 1), q(3, 5), and r(5, -5).

finlep [7]

The equation of the straight line is given by 5y-x=6

An equation can be used to describe a straight line drawn on the Cartesian Plane. These equations have a generic structure and can change based on the slope and where the line intersects the axes.

We will greatly simplify this issue by utilizing the fact that this triangle is specified as a right triangle. We would have had to establish the presence of a right angle if it had been presented as a general triangle.

The segment QR is the hypotenuse of the triangle.

Any side's altitude is located along a line that is perpendicular to that side. We are aware that the slopes of perpendicular lines are negative reciprocals, or:

Slope of line joining Q(3, 5) and R(5, -5)

m= $\frac{y_2-y_1}{x_2-x_1}$

Hence slope is= -10/2= -5

Now we know that for two perpendicular line the slope of one line is the negative reciprocal of the other.

Slope of line perpendicular to QR=1/5

This line passes through P(-1,1)

Equation of the straight line that passes through (1,-1) and with a slope of 1/5 is given by:

$(y-y_1)=m(x-x_1)\\$

Substituting the values we get:

y-1=1/5(x+1)

or,5y-5=x+1

or,5y-x=6

Hence the equation of the required line is : 5y-x=6

To learn more about straight lines visit:

brainly.com/question/17757770

#SPJ4

8 0

1 year ago

How do you work out this equation

Gnom [1K]

Answer:

x is equal to negative one, and y is equal to negative four.

Step-by-step explanation:

You can do this by solving one of the equations by either x or y, then substituting it into the other. Let's solve the second one for y:

$2y = 3x - 5\\y = \frac{3x - 5}{2}$

Now we'll substitute that into the first equation:

$9x - 2y = -1\\9x - 2(\frac{3x - 5}{2}) = -1\\9x - 3x + 5 = -1\\6x + 5 = -1\\6x = -6\\x = -1$

So we now know that x is equal to -1. We can simply substitute that into one of the original equations to find y:

$2y = 3x - 5\\2y = 3(-1) - 5\\2y = -3 - 5\\2y = -8\\y = -4$

We now know that x is equal to -1, and y is equal to -4. We can also check our answer by plugging that -4 into the other equation, and see if we still get -1:

$9x - 2y = -1\\9x - 2(-4) = -1\\9x + 8 = -1\\9x = -1 - 8\\9x = -9\\x = -1$

So we know that our answer is correct.

3 0

2 years ago

The slope of the line whose equation is 3y + 2x =1 is

frez [133]

3y + 2x =1
3y = - 2x + 1
y = - 2/3x + 1/3

slope : - 2/3

7 0

2 years ago