Answer:
a. The Mexican Airline offers a better deal for 9 students to travel.
b. 10 students
Step-by-step explanation:
a. The Mexican Air airline offers a round trip airfare of $250 per person.
So, for 9 students the fare will be total $(250 × 9) = $2250
Now, the Fiesta airline offers a round trip airfare of $150 per person if the club agrees to pay a one-time group rate processing fee of $1000.
So, for 9 students the total fare will be = $[1000 + (150 × 9)] =$2350.
Therefore, the Mexican Airline offers a better deal for 9 students to travel. (Answer)
b. Let for x students both the airline offers the same total costs.
Then we can write
250x = 1000 + 150x {From the conditions given}
⇒ 100x = 1000
⇒ x = 10
So, if the number of students is 10, then only both the airlines will take same fare. (Answer)
Answer:
Why is 3 an integer?
They are the numbers you usually count and they will continue on into infinity. Whole numbers are all natural numbers including 0 e.g. 0, 1, 2, 3, 4… Integers include all whole numbers and their negative counterpart e.g. … -4, -3, -2, -1, 0,1, 2, 3, 4
Answer:
65 gallons per minute
Step-by-step explanation:
The total volume of the tank at any given time is given by the equation:
V(t) = 65t + 280
In order to find the rate of change of volume, we can simply differentiate this equation with respect to time. This will give us the rate of change of the volume or the rate at which water is being pumped into the tank.
Differentiating the above equation we get:
V'(t) = 65
So we can see that the rate at which water is being pumped into the tank is 65 gallons per minute
Answer:
16 Tons
Step-by-step explanation:
divide 512,00 by 32000
Answer:
x= 0 , 
, 
Step-by-step explanation:
Given, equation is ![\sqrt[3]{15x-1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B15x-1%7D)
+ ![\sqrt[3]{13x+1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B13x%2B1%7D)
= ![4\sqrt[3]{x}](https://tex.z-dn.net/?f=4%5Csqrt%5B3%5D%7Bx%7D)
. →→→ (1)
Now, by cubing the equation on both sides, we get
( + )³ = ()³
⇒ (15x-1) + (13x+1) + 3×× ( + ) = 64 x.
⇒ 28x + 3×× () = 64x.
(since from (1), + = )
⇒ 12× × (![\sqrt[3]{x}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D)
)= 36x.
⇒ 3x = ![\sqrt[3]{(15x-1)(13+1)(x)}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%2815x-1%29%2813%2B1%29%28x%29%7D)
.
Now, once again cubing on both sides, we get
(3x)³ = ()³.
⇒ 27x³ = (15x-1)(13x+1)(x).
⇒ 27x³ = 195x³ + 2x² - x
⇒ 168x³ + 2x² - x = 0
⇒ x(168x² + 2x -1) = 0
⇒ by, solving the equation we get ,
x = 0 ; x = ; x =
therefore, solution is x= 0 , ,
