.hello :
an equation of the circle <span>Center at the w(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : r = 1
</span><span>The points (-18,15) and (-20,15) lie on a circle with a radius of 1:
</span>(-18-a)²+(15-b)² = 1 ....(1)
(-20-a)² +(15-b)² = 1 ....(2)
solve this system :
(1) -(2) : (-18-a)² - (-20-a)² =0
(-18-a)² =(-20-a)² =0
( -18-a = -20-a) or (-18-a = - (-20-a))
1 ) ( -18-a = -20-a) no solution confused : -18=-20
2 ) -18-a =20+a
-2a =38
a = -19
subst in (1) :(-18+19)²+(15-b)² =1
(15-b)² = 0.... 15-b = 0 .... b = 15
the center is :w(-19,15)

6 0

3 years ago

a scuba diver descended at a rate of 2 1/4 per second. If 0 represents the surface of the water and distances below the surface

Shtirlitz [24]

Answer:

The location will be at $- 28\frac{1}{8}$ units.

Step-by-step explanation:

A scuba diver descended at a rate of $2\frac{1}{4}$ units per second.

Now, if 0 represents the surface of the water and distances below the surface are negative, then after $12\frac{1}{2}$ seconds the location of the diver will be given by the followings :