Question

Find an equation of the line that (a) has y-intercept of -8 and (b) is parallel to the line 6 x − 1 y = 7 6x-1y=7 . Write your answer in the form y = m x + b y=mx+b .

Answer 1

Answer:

The equation of the line in the slope-intercept form is:

$\:y=6x-8$

Step-by-step explanation:

The slope-intercept form of the equation of a line is

$y\:=\:mx\:+\:b$

As y intercept is -8, we have

$y\:=\:mx\:-8$

Since the line is parallel to $6x-y=7$, then it has the same slope.

Let's put this equation in $y\:=\:mx\:+\:b$  form and find the slope

$6x-y=7$

$y=6x-7$

Thus, the slope is :

$m = 6$

Now we can finish the equation of the line in the slope-intercept form

$y\:=\:mx\:+\:b$

$\:y=6x-8$           ∵ $m = 6$, b = -8

Therefore, the equation of the line in the slope-intercept form is:

$\:y=6x-8$