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Alex787 [66]
3 years ago
7

Hey yall i need some help based on true or false .......The number 0 is the first natural number? (True or false)​

Mathematics
1 answer:
MariettaO [177]3 years ago
3 0

Answer:

False. The first natural number is 1.

Step-by-step explanation:

We start counting at 1, not 0.

Hope this helps!

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Ed is 7 years older than Ted. Ed’s age is also 1/3 times Ted’s age. How old are Ed and Ted?
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Ed is 13 Ted is 6

Step-by-step explanation:

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Solve the equation y=10x + 28.75
Alex17521 [72]

Answer:

x=y/10-2.875

slope=10

y= (0,28.75)

Standard form; 40x-4y=-115

Step-by-step explanation:

Not sure which answer you're looking for, but hope this helps!

5 0
3 years ago
WILL MARK BRAINLIEST <br> PLEASE HELP x
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Answer:

3. time = 6.4999  approximately 6.5 years

4. $2235.35

5.  $ 3950

Step-by-step explanation:

4. amount of interest =  final amount - principle= 7535.35 - 5300 = 2235.35

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7 0
4 years ago
The table shows the viscosity of an oil as a function of temperature. Identify a quadratic model for the viscosity, given the te
777dan777 [17]

Answer:

The viscosity at 140°C is predicted to be 7.2

Step-by-step explanation:

The function that model the relationship between viscosity and temperature = Quadratic model

The general form of a quadratic equation is y = a·x² + b·x + c

Therefore, we have;

When y = 10.8, x = 110, which gives;

10.8 = a·110² + b·110 + c = 12100·a + 110·b + c

10.8 = 12100·a + 110·b + c

When y =8.2, x = 130

8.2 = a· 130² + b· 130 + c = 16900·a + 130·b + c

8.2 = 16900·a + 130·b + c

When y = 160, x = 5.8

5.8 = a·160² + b·160 + c = 25600·a + 160·b + c

5.8 = 25600·a + 160·b + c

The three equations above can be listed as follows;

10.8 = 12100·a + 110·b + c

8.2 = 16900·a + 130·b + c

5.8 = 25600·a + 160·b + c

Solving using matrices gives;

\begin{bmatrix}12100 & 110 & 1\\ 16900 & 130 & 1\\ 25600 & 160 & 1\end{bmatrix} \begin{bmatrix}a\\ b\\ c\end{bmatrix} = \begin{bmatrix}10.8\\ 8.2\\ 5.8\end{bmatrix}

\begin{bmatrix}a\\ b\\ c\end{bmatrix} = -\dfrac{1}{3000}\begin{bmatrix}3 & -5 & 2\\ -867 & 1350 & -480\\ 62400 & -88000 & 28600\end{vmatrix} \begin{bmatrix}10.8\\ 8.2\\ 5.8\end{bmatrix}

From which we have;

a = 0.001, b = -0.37, c = 39.4

Substituting gives;

y = 0.001·x² - 0.37·x + 39.4

When x = 140

y = 0.962·140² - 0.37·140 + 39.4= 7.2

The viscosity at 140°C = 7.2.

8 0
3 years ago
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