Which of he following is proved by utilizing deductive reasoning ?

What happens to the value of the expression \dfrac5x+5 x 5 +5start fraction, 5, divided by, x, end fraction, plus, 5 as xxx de

aleksandr82 [10.1K]

Answer:

It increases

Step-by-step explanation:

(5/x) + 5

As x decreases, 5/x increases. So the expression increases.

5 0

4 years ago

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Completely factor the given expression over the integers.<br><br> (Correct gets brainliest)

elena-14-01-66 [18.8K]

Answer:

50

Step-by-step explanation:

would it be 50 because you the q to the power of 2 is 2q. Then you would subtract to the other side of the equation so it would be -100=-2q. After you would divided the -2 in -2q on both sides and -100/-2 is 50. So your answer is q=50

7 0

3 years ago

Put the numbers in order from least to greatest. - 29 , -5.39, - 27 5 , -5 7 20 A) - 27 5 , -5.39, - 29 , -5 7 20 B) - 29 , -5.3

lara [203]

Answer:

the answer is c starting with -5720

6 0

3 years ago

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A sample of blood pressure measurements is taken for a group of adults, and those values (mm Hg) are listed below. The values

Slav-nsk [51]

Answer:

Systolic on right

$\hat{CV} =\frac{18.68}{127.5}=0.147$

Systolic on left

$\hat{CV} =\frac{12.65}{74.2}=0.170$

So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.

Step-by-step explanation:

Assuming the following data:

Systolic (#'s on right) Diastolic (#'s on left)

117; 80

126; 77

158; 76

96; 51

157; 90

122; 89

116; 60

134; 64

127; 72

122; 83

The coefficient of variation is defined as " a statistical measure of the dispersion of data points in a data series around the mean" and is defined as:

$CV= \frac{\sigma}{\mu}$

And the best estimator is $\hat {CV} =\frac{s}{\bar x}$

Systolic on right

We can calculate the mean and deviation with the following formulas:

[te]\bar x = \frac{\sum_{i=1}^n X_i}{n}[/tex]

$s= \frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}$

For this case we have the following values:

$\bar x = 127.5, s= 18.68$

So then the coeffcient of variation is given by:

$\hat{CV} =\frac{18.68}{127.5}=0.147$

Systolic on left

For this case we have the following values:

$\bar x = 74.2 s= 12.65$

So then the coeffcient of variation is given by:

$\hat{CV} =\frac{12.65}{74.2}=0.170$

So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.

4 0

3 years ago

What is the slope of the line below

Fofino [41]

Answer:

C. $\frac{1}{2}$