Answer:
7. -
a. 3.5 or 7/2 hours
b. 24.5
c. After 7 hours (and at the beginning when t=0)
8. -
a. 4 seconds
b. 1 second
c. 54 meters
Step-by-step explanation:
7. M(t)=-2t^2+14t
M’(t)=-4t+14
a)
-4t+14=0
4t=14
2t=7
t=7/2
b) M(7/2)=24.5
c)
M(t)=0
-2t^2+14t=0
t^2-7t=0
t(t-7)=0
t=0, 7
8.
a)
h(t)=0
-6t^2+12t+48=0
t^2-2t-8=0
(t-4)(t+2)=0
t=-2, 4
t=4
b)
h(t)=-6t^2+12t+48
h’(t)=-12t+12
h’(t)=0
-12t+12=0
12t=12
t=1
c) h(1)=54
I hope this helps; please vote brainliest!
The first step is:
- determine how far from the house is young equestrian at noon.
2 x 10 = 20 miles
15 t = 20 + 10 t
15 t - 10 t = 20
5 t = 20
t = 20 : 5
t = 4 hours
Answer: at 4:00 PM.
X:2=24.3
x=24.3 • 2
x=48.6
Answer is 48.6
Answer:
approximately 21, when rounded to nearest tenth.
Step-by-step explanation:
First, let's find the measure of angle BAD. Angles BAD and DAC add up to 180 degrees, so 180-57= 123 degrees. Now, let's find the circumference of the circle. The circumference is diameter * π, which is 19.6(π). Then, the ratio is 123/360, so multiply 19.6(π) by 123/360, and you get 21.0381988...... which simplifies to 21 (rounded to nearest tenth)
Don't touch the center. It is already even.
Start anywhere by connecting a dotted line from one vertex to the next. To keep things so we know what we are talking about, go clockwise. Now you have 2 points that are Eulerized that were not before.
Skip and edge and do the same thing to the next two vertices. Those two become eulerized. Skip an edge and do the last 2.
Let's try to describe this better. Start at any vertex and number them 1 to 6 clockwise.
Join 1 to 2
Join 3 to 4
Join 5 to 6
I think 3 is the minimum.
3 <<<< answer
