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emmasim [6.3K]
3 years ago
6

I need help on 5 and 6

Mathematics
1 answer:
Blizzard [7]3 years ago
8 0

5. 4 rows of circles with 4 columns of circles


6. A Hexagon with 4 circles

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Which of the following equations is equivalent to the equation 6x-y=1
kondaur [170]
A. 6x-y=1 can go to 6x-y-1=0 and then 6x-1 = y 
3 0
3 years ago
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Una recta que pasa por los puntos A (2,1) y B (6,3) y otra recta pasa por A y por el punto (0,y) ¿Cuánto vale y, si ambas rectas
ASHA 777 [7]

The translation of the question given is

A line that passes through the points A (2,1) and B (6,3) and another line passes through A and through the point (0, y). What is y worth, if both lines are perpendicular?

Answer:

y = 5

Step-by-step explanation:

Line 1 that passes through A (2,1) and B (6,3)  

Slope (m1) = 3-1/6-2 = 2/4 = 1/2

y - 1 = \frac{1}{2} ( x -2)

2y - 2 = x- 2

y = \frac{x}{2}

Line 2 passes through A (2,1) and (0,y)

slope (m2) =\frac{y-1}{-2}

Line 1 and Line 2  are perpendicular

m1*m2 = -1

\frac{1}{2}  * \frac{y-1}{-2} = -1

y-1 = 4

y = 5

slope = -2

Equation of Line 2

Y-1 = -2(x-2)

y -1 = -2x +4

2x +y = 5

7 0
2 years ago
Someone please help me I suck @ simplifying thank you
ycow [4]
The anwer is 67/72 and can not be simpled any more
5 0
3 years ago
Two quantities vary inversely. If the value of the first is 15 when the value of the second is 18, find the value of the second
vovikov84 [41]

Answer:

The value of second quantity is 27

Step-by-step explanation:

Inverse variation can be represented by the equation xy=k or y = \frac{k}{x} i.e,

y varies inversely as x , if there is some nonzero constant k such that, xy =k or y = \frac{k}{x} where  x≠0 and y≠0.

Given: Two quantities vary inversely.

Let x be the first quantity and y be the second quantity if they  vary inversely.

then, by definition of inverse variation;

y = \frac{k}{x}            .....[1]

Substitute the value of x=15 and y=18 to solve for k;

18= \frac{k}{15}

Multiply both sides by 15 we have;

15\times 18=15 \times \frac{k}{15}

Simplify:

k=270

now, find  the second quantity y using same method when x=10.

then;

after substituting the value of x=10 and k=270 in [1] ;

y = \frac{270}{10}

Simplify:

y= 27

Therefore, the second quantity value i.e,y = 27



7 0
3 years ago
Read 2 more answers
- Write .0487 as a percent.<br> A)<br> 0.0487%<br> B)<br> 487%<br> C)<br> 4.87%<br> D)<br> 48.7%
Kay [80]

Answer:

D)

48.7%

Step-by-step explanation:

To convert the decimal to a percent, we multiply it by 1,000

0.0487 × 1,000 = 48.7

Hope I helped!

5 0
3 years ago
Read 2 more answers
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