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3 years ago

Six more than the quotient of a number b and 45 is grater than 4

Mathematics

1 answer:

Wewaii [24]3 years ago

6 0

$(b:45)+6>4\qquad\text{subtract 6 from both sides}\\\\\dfrac{b}{45}>-2\qquad\text{multiply both sides by 45}\\\\\boxed{b>-90}$

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Given f(x)=3x-1 find f(-1)

vaieri [72.5K]

Answer:

Step-by-step explanation:

f(x) = 3x - 1

To find f(-1) substitute the value of x that's

- 1 into f(x). That's for every x in f(x) replace it with - 1 and solve

That's

f( - 1) = 3(-1) - 1

= - 3 - 1

We have the final answer as

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3 years ago

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Nadya [2.5K]

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3 years ago

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3 years ago

Write each of the following as a function of theta.<br> 1.) sin(pi/4 - theta) 2.) tan(theta+30°)

Paladinen [302]

Step-by-step explanation:

Let x represent theta.

$\sin( \frac{\pi}{4} - x )$

Using the angle addition trig formula,

$\sin(x - y) = \sin(x) \cos(y) - \cos(x) \sin(y)$

$\sin( \frac{\pi}{4} ) \cos(x) - \cos( \frac{\pi}{4} ) \sin(x)$

$( \frac{ \sqrt{2} }{2}) \cos(x) - (\frac{ \sqrt{2} }{2} )\sin(x)$

Multiply one side at a time

Replace theta with x , the answer is

$\frac{ \sqrt{2} \cos(x) }{2} - \frac{ \sin(x) \sqrt{2} }{2}$

2. Convert 30 degrees into radian

$\frac{30}{1} \times \frac{\pi}{180} = \frac{\pi}{6}$

Using tangent formula,

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$\frac{ \tan(x) + \tan( \frac{\pi}{6} ) }{1 - \tan(x) \tan( \frac{\pi}{6} ) }$

Tan if pi/6 is sqr root of 3/3

$\frac{ \tan(x) + ( \frac{ \sqrt{3} }{3} ) }{1 - \tan(x) (\frac{ \sqrt{3} }{3} ) }$

Since my phone about to die if you later simplify that,

you'll get

$\frac{(3 \tan(x) + \sqrt{3} )(3 + \sqrt{3} \tan(x) }{3(3 - \tan {}^{2} (x) }$

Replace theta with X.

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2 years ago

Find a solution to the linear equation y equals 8x-32

Lerok [7]

Answer:

(4, 0).

Step-by-step explanation:

y = 8x - 32

There are many solutions that we can choose from, since any set of coordinates that fit in the equation counts as a solution.

We can have (0, -32), (1, -24), (2, -16), (3, -8), (4, 0), and many more.

Hope this helps!

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3 years ago

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