118 handle bars tells us that there's 118 bikes
if all 118 bikes were regular bikes
118*2 = 236
we would be 33 wheels short
118*1 = 118
we would be 17 seats short
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if 101 of the bikes are regular and 17 are tandem
101*1 = 101
17*2 = 34
we would have the right amount of seats
101*2 = 202
17*2 = 34
202 + 34 = 236
we would be 33 wheels short.
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if 17 bikes are tandem, 33 are tricycle, and 68 are regular
17*2 = 34
33*3 = 99
68*2 = 136
we would have the right amount of wheels
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Answer:
There are 68 bicycles, 17 tandem bicycles, and 33 tricycles.
This question isn't hard, it just takes longer since it's based off of guess and check.
6cups of flour will be needed
5*12/4= 15
90/15=6
Let p be the prize of a pen and m the prize of a mechanical pencils. If you buy six pens and one mechanical pencil, you spend 6p+m. We know that this equals 9, because you get 1$ change from a 10$ bill.
Similarly, if you buy four pens and two mechanical pencils, you spend 4p+2m, which is 8$, because now you get a $2 change. Put these equation together in a system:
Now, if you multiply the first equation by 2, the system becomes
Subtract the second equation from the first:
Plug this value into the first equation to get
D
This is because the expression can be simplified to get the same result. -1+2log_4((1/4)x)
P = 2L + 2W ....subtract 2L from both sides
P - 2L = 2W ...divide both sides by 2
(P - 2L) / 2 = W .....can also be written like (P/2) - L = W
