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hammer [34]
3 years ago
15

Help please!!!

Mathematics
1 answer:
marysya [2.9K]3 years ago
4 0

Answer:

see explanation

Step-by-step explanation:

Given the 2 equations

y = x² + 2x + 7 → (1)

y - 7 = x → (2)

Rearrange (2) expressing y in terms of x by adding 7 to both sides

y = x + 7 → (3)

Substitute y = x + 7 into (1)

x + 7 = x² + 2x + 7 ( subtract x + 7 from both sides )

0 = x² + x ← factor out x from each term

0 = x(x + 1)

Equate each factor to zero and solve for x

x = 0

x + 1 = 0 ⇒ x = - 1

Substitute these values into (3) for corresponding values of y

x = 0 → y = 0 + 7 = 7

x = - 1 → y = - 1 + 7 = 6

The solutions are

(- 1, 6 ) and (0, 7 )

You might be interested in
0.25 and 1/8 closets to 0,1,2 or 3
s2008m [1.1K]
Not sure what you are asking but 0.25 and 1/8 are closer to 1 than they are 2
7 0
4 years ago
If -2 and 3 are zeroes of quadratic polynomial xsquare + (a+1)x+b then find the value of and b
ohaa [14]

Answer:

a = - 2, b = - 6

Step-by-step explanation:

Substitute the values of the zeros into the polynomial and equate to zero.

x² +(a + 1)x + b

x = - 2 → (- 2)² - 2(a + 1) + b = 0 , that is

4 - 2a - 2 + b = 0

2 - 2a + b = 0 ( subtract 2 from both sides )

- 2a + b = - 2 → (1)

x = 3 → 3² + 3(a + 1) + b = 0, that is

9 + 3a + 3 + b = 0

12 + 3a + b = 0 ( subtract 12 from both sides )

3a + b = - 12 → (2)

Subtract (1) from (2) term by term to eliminate b

5a = - 10 ( divide both sides by 5 )

a = - 2

Substitute a = - 2 into either of the 2 equations and evaluate for b

Substituting into (2)

3(- 2) + b = - 12

- 6 + b = - 12 ( add 6 to both sides )

b = - 6

Thus a = - 2 and b = - 6

4 0
4 years ago
Helppppppppppppppppppppppppppppp Fasttttt
sertanlavr [38]
What you have to do is multiply each of the sides so you have 80, 60, and 48.

Add those up to get 188. Then multiply this by 2 and you get 376.

Your answer is D. (376)

P.S if this helped you out, please give me brainliest if you don't mind. I am only a few more from leveling up :D
5 0
4 years ago
Can someone help me out with this? I’m not sure what I’m doing wrong.
Nadusha1986 [10]

Answer:


Step-by-step explanation:

This is a system of inequalities such that:

\left \{ {{2x+3y\geq 2} \atop {3x-4y\leq 3}} \right.

Let's start by solving for y for both equations:

Equation 1:

2x+3y\geq  2\\\\3y\geq -2x+2\\\\y \geq \frac{-2x+2}{3}

Equation 2:

3x-4y\leq 3\\\\-4y\leq -3x+3\\\\y\geq -\frac{(-3x+3)}{4}


Now if we substitute the 2nd y into the first equation we obtain:

2x+3(\frac{3x-3}{4}) \geq  2\\\\2x+\frac{9x-9}{4}\geq 2\\\\\frac{8x+9x-9}{4}\geq 2\\\\17x-9\geq 8\\\\17x\geq 17\\\\x\geq 1


Now we will solve for the second equation using the first result of y and we obtain:

3x-4(\frac{-2x+2}{3}\leq 3\\\\3x+\frac{8x-8}{3}\leq 3\\\\\frac{9x+8x-8}{3}\leq 3\\\\17x-8\leq 9\\\\17x\leq 17\\\\x\leq 1

And so our solution for the system of equations is:

x \leq 1\\and \\y\geq \frac{-2x+2}{3}

As well as:

x>1\\and\\y\geq \frac{3x-3}{4}


4 0
4 years ago
The Nashville Humane Society records the weights of 250 cats that are taken in during the month of July. The mean weight of the
skelet666 [1.2K]

Answer: D

Step-by-step explanation:

1875/250

= 7.5

total combined weight/amount of cats

= mean

7 0
3 years ago
Read 2 more answers
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