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tester [92]
3 years ago
8

Find the 16th term for the sequence a(n)=7-2n.

Mathematics
2 answers:
IRISSAK [1]3 years ago
8 0
Just plug in 16 for  n

a(16) = 7 - 2(16)

a(16) = 7 - 32

a(16) = -25

so the answer is -25
N76 [4]3 years ago
3 0
In the expression that you are given, n is the is number in the sequence. So in this scenario, n=16. So substitute the 16 into the equation. a(n)=7-2(16)=7-32=-25. So the 16th term in the sequence is -25.
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Answer:

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Step-by-step explanation:

c < 5 1/2

This means we have less than 5 1/2 of something

We have less than 5 /12 cups of sugar

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Step-by-step explanation:

55 + x + 74 + 54 = 180

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Secants AC and DB intersect at point E inside the circle. Given that the measure of arc CD = 40o, arc AB = 60o, and arc BC = 160
s344n2d4d5 [400]

Answer:

C. 130^{\circ}

Step-by-step explanation:

Please find the attachment.

We have been given that secants AC and DB intersect at point E inside the circle. Given that the measure of arc CD = 40^o, arc AB = 60^o, and arc BC = 160^o. We are asked to find the measure of angle AED.

We know that the measure of angle formed by two intersecting secants is half the sum of measure of the arcs by intercepted by the angle and its vertical angle.    

\angle AED=\frac{\widehat{BC}+\widehat{AD}}{2}

Let us find measure of arc AD by subtracting measure of given arcs from 360 degrees as:

\widehat{AD}=360^{\circ}-(60^{\circ}+40^{\circ}+160^{\circ})

\widehat{AD}=360^{\circ}-(260^{\circ})

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\angle AED=\frac{260^{\circ}}{2}

\angle AED=130^{\circ}

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Step-by-step explanation:

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3 years ago
solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations. x-2y+
Alekssandra [29.7K]

Answer:

x = -5, y = -6, z = -3

Step-by-step explanation:

Given the system of three equations:

\left\{\begin{array}{l}x-2y+3z=-2\\6x+2y+2z=-48\\x+4y+3z=-38\end{array}\right.

Write the augmented matrix for the system of equations

\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)

Find the reduced row-echelon form of the augmented matrix for the system of equations:

\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)\sim \left(\begin{array}{ccccc}1&-2&3&|&-2\\0&-14&16&|&36\\0&-6&0&|&36\end{array}\right)\sim \left(\begin{array}{ccccc}1&3&-2&|&-2\\0&16&-14&|&36\\0&0&-6&|&36\end{array}\right)

Thus, the system of three equations is

\left\{\begin{array}{r}x+3z-2y=-2\\16z-14y=36\\-6y=36\end{array}\right.

From the last equation:

y=-6

Substitute it into the second equation:

16z-14\cdot (-6)=36\\ \\16z=36-84\\ \\16z=-48\\ \\z=-3

Substitute y = -6 and z = -3 into the first equation:

x+3\cdot (-3)-2\cdot (-6)=-2\\ \\x=-2+9-12\\ \\x=-5

7 0
3 years ago
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