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tester [92]
3 years ago
8

Find the 16th term for the sequence a(n)=7-2n.

Mathematics
2 answers:
IRISSAK [1]3 years ago
8 0
Just plug in 16 for  n

a(16) = 7 - 2(16)

a(16) = 7 - 32

a(16) = -25

so the answer is -25
N76 [4]3 years ago
3 0
In the expression that you are given, n is the is number in the sequence. So in this scenario, n=16. So substitute the 16 into the equation. a(n)=7-2(16)=7-32=-25. So the 16th term in the sequence is -25.
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1. Which of the following points is a solution of y > |x| + 5?
Dennis_Churaev [7]
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7 0
3 years ago
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I need the answer for this exact question
denis23 [38]

Answer:

y=\frac{7}{2}x-20

Step-by-step explanation:

Let the equation of the line be y-y_1=m(x-x_1) where, 'm' is its slope and (x_1,y_1) is a point on it.

Given:

The equation of a known line is:

y=-\frac{2}{7}x+9

A point on the unknown line is:

(x_1,y_1)=(4,-6)

Both the lines are perpendicular to each other.

Now, the slope of the known line is given by the coefficient of 'x'. Therefore, the slope of the known line is m_1=-\frac{2}{7}

When two lines are perpendicular, the product of their slopes is equal to -1.

Therefore,

m\cdot m_1=-1\\m=-\frac{1}{m_1}\\m=-\frac{1}{\frac{-2}{7} }=\frac{7}{2}

Therefore, the equation of the unknown line is determined by plugging in all the given values. This gives,

y-(-6))=\frac{7}{2}(x-4)\\y+6=\frac{7}{2}x-14\\y=\frac{7}{2}x-14-6\\\\y=\frac{7}{2}x-20

The equation of a line perpendicular to the given line and passing through (4, -6) is y=\frac{7}{2}x-20.

3 0
3 years ago
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AlladinOne [14]

Answer:

9

Step-by-step explanation:

36 ÷ 4 = 9

36 ÷ 9 = 4

4 0
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denis23 [38]

Answer:

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(x,y)

7 0
3 years ago
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The answers pls <br>and pls again
dlinn [17]
3. 27 because 18+9=27
5 0
3 years ago
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