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Andrew [12]
3 years ago
5

A square floor has a side length of 7x5y6 units. A square tile has a side length of x2y units. How many tiles will it take to co

ver the floor? Express your answer in simplified form.
Mathematics
1 answer:
AysviL [449]3 years ago
8 0

It will take 49x^{6}y^{10} tiles to cover the floor

<em>Given the following:</em>

side length of the square floor - 7x^5y^6 units

side length of square tile - x^2y units

First, find the area of the square floor and square tile:

Area of the square floor = area of a square = s^2

Where, s = 7x^5y^6

Plug in the value into the formula

Area of the square floor = (7x^5y^6)^2

= 49x^{10}y^{12} sq units

Area of the square tile = area of a square = s^2

Where, s = x^2y

Plug in the value

Area of the square tile = (x^2y)^2

= x^4y^2 sq units

Next, find the number of tiles it will take to cover the floor by dividing the area of the square floor by the area of the square tile.

= \frac{ 49x^{10}y^{12}}{x^4y^2}

Simplify

= 49x^{6}y^{10}

The number of tiles to cover the floor would be expressed as = 49x^{6}y^{10} tiles

Learn more about area of a square here:

brainly.com/question/17554162

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