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Luden [163]
3 years ago
6

Five times the smaller of two consecutive numbers is added to 3 times the bigger, the result is 579. Find the smaller integer.

Mathematics
1 answer:
dezoksy [38]3 years ago
4 0
To solve this problem you must apply the proccedure shown below:

 1. You have the following informatioon given in the problem above:

 - <span>Five times the smaller of two consecutive numbers is added to 3 times the bigger.
 - The result is 579. 

 2. Keeping this on mind, you have the following equation:

 x: the smaller number.

 5x+3(x+1)=579

 3. You must solve for x to calcualte the value of the smaller integer:

 5x+3x+3=579
 8x+3=579
 8x=579-3
 x=576/8
 x=72

 The answer is: 72
 </span>
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Answer:

1. In the multiplication of the imaginary parts, the student forgot to square of i. OR

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Correct value =22+7i.

Step-by-step explanation:

The given expression is

(4+5i)(3-2i)

A student multiplies (4+5i) (3-2i) incorrectly and obtains 12-10i.

Student's mistake can be either 1 or second:

1. In the multiplication of the imaginary parts, the student forgot to square of i.

2. The student has only multiplied the real parts and the imaginary parts.

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Which is not correct. The correct steps are shown below.

Using distributive property, we get

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12+7i+10

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