3 years ago

If f(x-1) = 2x+3 for all values of x, what is the value of f(-3)?

Mathematics

1 answer:

stiks02 [169]3 years ago

7 0

$f(x-1)=2x+3 \\ f(-2-1)=2 \cdot (-2)+3 \\ f(-3)=-4+3=-1 \\ answer \ D)$

You might be interested in

Please help me with this

Eduardwww [97]

Answer:

$r^{6}$

Step-by-step explanation:

Using the rule of exponents

$\frac{a^{m} }{a^{n} }$ = $a^{(m-n)}$ , then

$\frac{r^{9} }{r^{3} }$ = $r^{(9-3)}$ = $r^{6}$

5 0

2 years ago

A right triangle has a base that measure 39 inches and a height that measures 80 inches. What is the length of its hypotenuse?

guajiro [1.7K]

The Pythagorean Theorum formula is a(squared) + b(squared)= c(squared). If you plug in the numbers, the equation is 39(squared) + 80(squared)= c(squared). That simplifies to 1521+6400=c(squared). Adding results in 7921=c(squared). Finally, when you take the square root of both sides, you are left with 89=c (aka the hypotenuse)

5 0

2 years ago

Use the given domain to find the range of function: f(x)=−2x²+7, D={2, −3, 0}

soldi70 [24.7K]

Answer:

R={-1, -11, 7}

Step-by-step explanation:

-2(2)^2+7=

-2(4)+7=

-8+7=

-1

-2(-3)^2+7=