a circle has a radius of 10 yards what is the circumference of the circle? express your answer using pie

+ x = 12 – 2x what is this?

AleksAgata [21]

Answer:

x= -6

Step-by-step explanation:

7 0

2 years ago

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*****Write a polynomial using the roots -3,5i. PLEASE HELP IM SO LOST!!!

Vladimir79 [104]

The polynomial $(x-a)$ has a unique root, $a$ , for any $a$ .

Hence $(x+3)(x-5i)$ is a polynomial with roots $-3$ and $5i$

8 0

3 years ago

F=5/4(n-90) Find n Helppp

padilas [110]

Answer:

n= 4f/5+90

Step-by-step explanation:

f= 5(n−90) /4 (simplify)

f * 4=5(n−90) (multiply 4 on both sides)

4f=5(n−90) (regroup)

4f/5 =n−90 (divide 5 on both sides)

4f/5 +90=n (add 90 to both sides)

4 0

3 years ago

ABC is a right triangle. If AC = 12 and BC = 13, find AB.

AysviL [449]

Since BC is the hypotenuse...

α = 12
c = 13

Hence..

13² = 12² + ß²
ß = √(13² - 12²)
= √(169 - 144)
= √25
= 5

Hence, AB = 5

I hope this helps!

3 0

3 years ago

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A survey of 700 adults from a certain region asked, "What do you buy from your mobile device?" The results indicated that 59%

Kryger [21]

Answer:

a) the test statistic z = 1.891

the null hypothesis accepted at 95% level of significance

b) the critical values of 95% level of significance is zα =1.96

c) 95% of confidence intervals are (0.523 ,0.596)

Step-by-step explanation:

A survey of 700 adults from a certain region

Given sample sizes $n_{1} = 400 and n_{2} = 300$

Proportion of mean $p_{1} = \frac{236}{400} = 0.59 and p_{2} = \frac{156}{300} = 0.52$

Null hypothesis H0 : assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

Alternative hypothesis H1:- p1 ≠ p2

a) The test statistic is

$Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )} } }$

where $p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}$

on calculation we get p = 0.56

now q =1-p = 1-0.56=0.44

$Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )} } }\\ =\frac{0.56-0.52}{\sqrt{0.56X0.44}(\frac{1}{400}+\frac{1}{300} }$

after calculation we get z = 1.891

b) The critical value at 95% confidence interval zα = 1.96 (from z-table)

The calculated z- value < the tabulated value

therefore the null hypothesis accepted

conclusion:-

assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

c) 95% confidence intervals

The confidence intervals are P± 1.96(√PQ/n)

we know that = $p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}$

after calculation we get P = 0.56 and Q =1-P =0.44

Confidence intervals are ( P- 1.96(√PQ/n), P+ 1.96(√PQ/n))

now substitute values , we get

( 0.56- 1.96(√0.56X0.44/700), 0.56+ 1.96(0.56X0.44/700))

on simplification we get (0.523 ,0.596)

Therefore the population proportion (0.56) lies in between the 95% of confidence intervals (0.523 ,0.596)

3 0

3 years ago