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goblinko [34]
3 years ago
13

Two rectangles have the same area of 24cm².The second rectangle is 4cm shorter and 1cm wider than the first.What is the length a

nd breadth of both triangles
Mathematics
1 answer:
lukranit [14]3 years ago
5 0

Answer:

  First rectangle: 12 cm by 2 cm

  Second rectangle: 8 cm by 3 cm

Step-by-step explanation:

You can examine factor pairs of 24 to see which pairs meet the requirements:

  24 = 1×24 = 2×12 = 3×8 = 4×6

Factor pairs (2, 12) and (3, 8) have one factor that differs by 1 and another factor that differs by 4. We can use these numbers to describe the rectangles:

  First rectangle: 12 cm by 2 cm

  Second rectangle: 8 cm by 3 cm

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The square root of 5 is 2.23, or just 2.


I hope I helped!

Step-by-step explanation:


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Step-by-step explanation:

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Heng tried to define a reflection across line r.
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Answer:

Any point N on line r maps to itself.

Step-by-step explanation:

Reflection is one of the examples of solid transformation in which a given point, segment, or figure is flipped over a reference point or line to produce its image. The distance of the object to the reference point or line is the same as the distance of its image to the point or line. And both have the same size, but different orientation.

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A line has a measurable length true or false
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The length of a rectangle is 2 times it’s width if the perimeter of the rectangle is 36 inches find it’s length and width
Tamiku [17]

P = Perimeter            

L = Length          

W = Width

Perimeter of rectangle = L + L + W + W        

or P = 2L + 2W

You know:

P = 36 inches

L = 2W          [length is(=) 2 times it's width]

W = ?

P = 2L + 2W    

Substitute/plug in what you know, plug in 2W for L since L = 2W

36 = 2(2W) + 2W         Simplify

36 = 4W + 2W

36 = 6W        Divide 6 on both sides

6 = W              Now that you know the width, you can find the length:

L = 2W

L = 2(6)

L = 12

L = 12 in

W = 6 in

PROOF

P = 2(12) + 2(6)

P = 24 + 12

P = 36

6 0
3 years ago
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