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goblinko [34]
3 years ago
13

Two rectangles have the same area of 24cm².The second rectangle is 4cm shorter and 1cm wider than the first.What is the length a

nd breadth of both triangles
Mathematics
1 answer:
lukranit [14]3 years ago
5 0

Answer:

  First rectangle: 12 cm by 2 cm

  Second rectangle: 8 cm by 3 cm

Step-by-step explanation:

You can examine factor pairs of 24 to see which pairs meet the requirements:

  24 = 1×24 = 2×12 = 3×8 = 4×6

Factor pairs (2, 12) and (3, 8) have one factor that differs by 1 and another factor that differs by 4. We can use these numbers to describe the rectangles:

  First rectangle: 12 cm by 2 cm

  Second rectangle: 8 cm by 3 cm

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Which of the following equations do not represent a proportional relationship?
Dmitry [639]
The correct answer for the question is y=x
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3 years ago
If someone could work out the first half of the problem and explain that would be great!
andrew-mc [135]

Answer:

x = -5

y = -5

Step-by-step explanation:

If you multiply the top equation by negative 2, you can add it to the bottom equation and cancel out the x:

-2(-x + 5y = -20) --> 2x - 10y = 40

Add this to the bottom equation top to bottom:

2x - 10y = 40

-2x + 4y = -10

You get:

-6y = 30

Then solve for y:

y = -5

Plug this back in for either equation and solve for x:

-x + 5(-5) = -20

-x -25 = -20

-x = 5

x = -5

Your answers are:

x = -5

y = -5

7 0
3 years ago
Read 2 more answers
CORRECT ANSWER GETS 95 POINTS AND BRAINLIEST
ollegr [7]

Answer:

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6 0
3 years ago
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The Candela brothers own two pizza restaurants, one on Park Street and one on Bridge Road.
koban [17]

The mean, median and mode are measures of central tendency, that is they tend to indicate the location middle of the data

Required values;

(a) The performance for the week for Park Street

  • Revenue is <u>Q₂ < $7,500 < Q₃</u>
  • The sales for the week is better than <u>72.91%</u> of all sales

The performance for the week for Bridge Road

  • Revenue; <u>Q₂ < $7,100 < Q₃</u>
  • The sale for the week is better than <u>59.87%</u> of all sales

(b) The mean is <u>$3611</u>

The median is $<u>3,600</u>

The standard deviation is $<u>3250</u>

The Interquartile range is $<u>6075</u>

Reason:

The table of values that maybe used to find a solution to the question is given as follows;

\begin{array}{|l|l|l|}\mathbf{Variable} &\mathbf{Park}&\mathbf{Bridge}\\N&36&40\\Mean&6611&5989\\SE \ Mean&597&299\\StDev&3580&1794\\Minimum&800&1800\\Q_1&3600&5225\\Median&6600&6000\\Q_3&9675&7625\\Maximum&14100&8600\end{array}\right]

(a) Park Street revenue = $7,500

Bridge Road's revenue = $7,100

The two stores sold close to but below the 75th percentile

Bridge Road revenue;

The z-score is given as follows;

Z = \dfrac{x - \mu }{\sigma }

  • Z = \dfrac{7100 - 5,989 }{1794 } \approx 0.6193

From the Z-Table, we have;

The percentile= 0.7291

  • Therefore, the sale for the week for Park Street is better than <u>72.91%</u> of all the sales

Park Street revenue;

The z-score is given as follows;

  • Z = \dfrac{7500 - 6611}{3580} \approx 0.25

From the Z-Table, we have;

The percentile = <u>0.5987</u>

  • Therefore, the sale for the week is better than <u>59.87 %</u> of all the sales

(b) Given that the operating cost is $3,000, frim which we have;

The subtracted value is subtracted from the mean and median to find the new value

Profit = The revenue - Cost

New mean = 6611 - 3000 = 3611

  • The new mean = <u>$3,611</u>

The new median = 6600 - 3000 = 3600

  • The new median = <u>$3,600</u>

The standard deviation and the interquartile range remain the same, therefore, we have;

  • The standard deviation = <u>$3,580</u>

The interquartile range = 9675 - 3600 = 6075

  • The interquartile range = <u>6075</u>

Learn more here:

brainly.com/question/21133077

brainly.com/question/23305909

5 0
2 years ago
Find k if (x+1) 2x^3+kx^2+1
Viktor [21]
<h2>Question:</h2>

Find k if (x+1) is a factor of 2x³ + kx² + 1

<h2>Answer:</h2>

k = 1

<h2>Step-by-step explanation:</h2>

The factor of a polynomial F(x) is another polynomial that divides evenly into F(x). For example, x + 3 is a factor of the polynomial x² - 9.

<em>This is because;</em>

i. x² - 9 can be written as (x - 3)(x + 3) which shows that both (x - 3) and (x + 3) are factors.

ii. If x = -3 is substituted into the polynomial x² - 9, the result gives zero. i.e

=> (-3)² - 9

=> (9) - 9 = 0

Therefore, if (x + a) is a factor of a polynomial, substituting x = -a into the polynomial should result to zero. This also means that, if x - a is a factor of a polynomial, substituting x = a into the polynomial should give zero.

<em><u>From the question</u></em>

Given polynomial: 2x³ + kx² + 1

Given factor: x + 1.

Since x + 1 is a factor of the polynomial, substituting x = -1 into the polynomial should give zero and from there we can calculate the value of k. i.e

2(-1)³ + k(-1)² + 1 = 0

2(-1) + k(1) + 1 = 0

-2 + k + 1 = 0

k - 1 = 0

k = 1

Therefore the value of k is 1.

3 0
2 years ago
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