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goblinko [34]
3 years ago
13

Two rectangles have the same area of 24cm².The second rectangle is 4cm shorter and 1cm wider than the first.What is the length a

nd breadth of both triangles
Mathematics
1 answer:
lukranit [14]3 years ago
5 0

Answer:

  First rectangle: 12 cm by 2 cm

  Second rectangle: 8 cm by 3 cm

Step-by-step explanation:

You can examine factor pairs of 24 to see which pairs meet the requirements:

  24 = 1×24 = 2×12 = 3×8 = 4×6

Factor pairs (2, 12) and (3, 8) have one factor that differs by 1 and another factor that differs by 4. We can use these numbers to describe the rectangles:

  First rectangle: 12 cm by 2 cm

  Second rectangle: 8 cm by 3 cm

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The distance between X and Y is 6 1/2 units. Which number could represent the point Y?
tiny-mole [99]

Answer:

\huge\boxed{\sf 3.5}

Step-by-step explanation:

Distance = \sf 6 \frac{1}{2} \ units = 6.5 \ units

Here X is -3

So,

Point Y = -3 + 6.5 = 3.5

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
6 0
3 years ago
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Your swimming pool containing 60,000 gal of water has been contaminated by 6 kg of a nontoxic dye that leaves a swimmer's skin a
Paul [167]

[a] Dye is removed from the pool at a rate of

(250 gal/min) * (<em>q</em>/60,000 g/gal) = -<em>q</em>/240 g/gal

where <em>q</em> denotes the amount of dye in the pool at time <em>t</em>. Clean water is pumped back into the pool, so no dye is being re-added.

So the net rate of change of the amount of dye in the pool is given by the differential equation,

\dfrac{\mathrm dq}{\mathrm dt}=-\dfrac{q(t)}{240}

with the intial value, <em>q</em>(0) = 6000 g (or 6 kg).

[b] The ODE above is separable as

\dfrac{\mathrm dq}q=-\dfrac{\mathrm dt}{240}

Integrate both sides to get

\ln|q|=-\dfrac t{240}+C

e^{\ln|q|}=e^{-t/240+C}

\implies q(t)=e^{-t/240+C}=e^{-t/240}e^C=Ce^{-t/240}

Now plug in the initial condition:

6000=Ce^0\implies C=6000

so the particular solution to the IVP is

q(t)=6000e^{-t/240}

[c] The acceptable concentration of the dy is 0.03 g/gal, which in a pool containing 60,000 gal of water corresponds to

(0.03 g/gal) * (60,000 gal) = 1800 g = 1.8 kg

of dye. Find the time <em>t</em> when this occurs:

1800=6000e^{-t/240}\implies0.3=e^{-t/240}

\implies\ln0.3=-\dfrac t{240}

\implies t=-240\ln0.3\approx288.953

so the amount of dye in the pool is within the acceptable tolerance after about 289 min have passes, or about 4.82 hrs. So no, the filtration system is not up to the task.

8 0
3 years ago
Read 2 more answers
Hey.. I’m really stuck on this page of homework, can anyone help?
eduard

Answer:

Easy!

Step-by-step explanation:

All you have to do is..       Percentage = (number you want to find the percentage for ÷ total) × 100. Move the decimal point two places to the right to convert from a decimal to a percentage, and two places to the left to convert from a percentage to a decimal.

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2 years ago
Please answer this correctly
GREYUIT [131]
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3 years ago
Find the volume of the cylinder
valkas [14]
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