Let l and w be the length and width of the rectangle. We are given the proportion 2l=4w, which implies l=2w.
The perimeter of a rectangle is given by 2(l+w). We know that the perimeter is 80, and we can plug l=2w to get
![2(l+w)=80 \iff 2(2w+w)=80 \iff 3w=40 \iff w=\dfrac{40}{3}](https://tex.z-dn.net/?f=2%28l%2Bw%29%3D80%20%5Ciff%202%282w%2Bw%29%3D80%20%5Ciff%203w%3D40%20%5Ciff%20w%3D%5Cdfrac%7B40%7D%7B3%7D)
Which, in turn, implies that
![l=2w=\dfrac{80}{3}](https://tex.z-dn.net/?f=l%3D2w%3D%5Cdfrac%7B80%7D%7B3%7D)
It's B. Since the slope is -8/1 x. Slope is rise/run. The other answers doesn't make sense since the x is put in a different place.
Answer:
1.00 meter.
Step-by-step explanation:
For the first day, she dug eighteen twentieth of a meter =
x 1 meter
=
meters
The second day, she dug nine twentieth of a mater =
x 1 meter
=
meters
Total length of the trench =
+ ![\frac{9}{20}](https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7B20%7D)
= ![\frac{18 + 9}{20}](https://tex.z-dn.net/?f=%5Cfrac%7B18%20%2B%209%7D%7B20%7D)
= ![\frac{27}{20}](https://tex.z-dn.net/?f=%5Cfrac%7B27%7D%7B20%7D)
= 1![\frac{7}{20}](https://tex.z-dn.net/?f=%5Cfrac%7B7%7D%7B20%7D)
= 1.35 meters
Total length of the trench is 1.35 meters.
A reasonable estimate of the total length of the trench is 1.00 meter.
Answer:
d ) f(x)= -5x-19 is most likely