3 years ago

Help me please help me

Mathematics

1 answer:

scoundrel [369]3 years ago

8 0

Answer:

Step-by-step explanation:

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Answer:

See below for answers and explanations

Step-by-step explanation:

Part A

Assuming that conditions have been met for the interval, we use the formula $\displaystyle CI=\bar{x}\pm t\frac{s}{\sqrt{n}}$ where $\bar{x}$ represents the sample mean, $t$ represents the critical value, $s$ represents the sample standard deviation, and $n$ is the sample size.

The critical value of $t$ for an 80% confidence level with degrees of freedom $df=n-1=25-1=24$ is equivalent to $t=1.317836$

Thus, we can compute the confidence interval:

$\displaystyle CI=\bar{x}\pm t\frac{s}{\sqrt{n}}\\\\CI=32.64\pm1.317836\biggr(\frac{9.39}{\sqrt{25}}\biggr)\\\\CI\approx\{30.17,35.11\}$

Therefore, we are 80% confident that the true mean age of all customers is between 30.17 and 35.11 years.

Part B

The margin of error is $\displaystyle t\frac{s}{\sqrt{n}}=1.317836\biggr(\frac{9.39}{\sqrt{25}}\biggr)\approx2.47$

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