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dalvyx [7]
3 years ago
15

workers at a hardware store take their morning break no earlier than 10am and no later than noon let b represent the actual time

they take their break
Mathematics
2 answers:
almond37 [142]3 years ago
8 0

"<" means the number on the left is smaller than the number on the right;

10am < b < 12pm

In this case that means "b" would be in between these times

Arlecino [84]3 years ago
4 0

Answer:

Time they take their break = b

b > 10.00\\b\leq 12.00\\10.00 < b \leq 12.00

Step-by-step explanation:

The problem shows that workers can take a morning break. We can represent the time of morning break with b.  

Let's express the time as real numbers. So 10 am or 10:00 will be 10.00.

Non 12:00 m will be 12.00.

The problem shows that morning break should not be earlier than 10 am. It means b should be strictly greater than 10.00 b > 10.00.

The problem mentions that morning break should not be later than noon. it means b should be less or equal than 12.00 b \leq 12.00

Now, if we join both intervals

b > 10.00\\b\leq 12.00\\10.00 < b \leq 12.00

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The demand equation illustrates the price of an item and how it relates to the demand of the item.

  • The slope of the demand function is -1/2
  • The equation of the demand function is: R(x) = (300 - 10x) \times (20 + 5x)
  • The price that maximizes her revenue is: Ghc 85

From the question, we have:

Plates = 300

Price = 20

The number of plates (x) decreases by 10, while the price (y) increases by 5. The table of value is:

\begin{array}{cccccc}x & {300} & {290} & {280} & {270} & {260} \ \\ y & {20} & {25} & {30} & {35} & {40} \ \end{array}

The slope (m) is calculated using:

m = \frac{y_2 - y_1}{x_2 - x_1}

So, we have:

m = \frac{25-20}{290-300}

m = \frac{5}{-10}

m = -\frac{1}{2}

The equation of the demand is as follows:

The initial number of plates (300) decreases by 10 is represented as: (300 - 10x).

Similarly, the initial price (20) increases by 5 is represented as: (20 + 5x).

So, the demand equation is:

R(x) = (300 - 10x) \times (20 + 5x)

Open the brackets to calculate the maximum revenue

R(x) =6000 + 1500x - 200x - 50x^2

R(x) =6000 + 1300x - 50x^2

Equate to 0

6000 + 1300x - 50x^2 =0

Differentiate with respect to x

1300 - 100x =0

Collect like terms

100x =1300

Divide by 100

x =13

So, the price at maximum revenue is:

Price= 20 + 5x

Price= 20 + 5 * 13

Price= 85

In conclusion:

  • The slope of the demand function is -1/2
  • The equation of the demand function is: R(x) = (300 - 10x) \times (20 + 5x)
  • The price that maximizes her revenue is: Ghc 85

Read more about demand equations at:

brainly.com/question/21586143

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