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1 year ago

Please help and answer it in a sentence :)

Mathematics

1 answer:

Alexandra [31]1 year ago

7 0

Answer:

x = $1 & y = $2.

Each doughnut cost $1 and hot chocolate cost $2.

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Does x*x*x*x*x = 5x?<br> I'm not really sure so it would help.

hodyreva [135]

Answer:

Step-by-step explanation:

no ,x*x*x*x*x=x^5

x+x+x+x+x=5x

in multiplication those who have same base we add their power.

in addition those variables which have same base(or are like term) we add them.

6 0

2 years ago

What is the area in cm^2 of the circle shown above

GaryK [48]

Answer:

Step-by-step explanation:

6 0

2 years ago

Which statement is true about the value of (6)? A.(6) greater-than 6

Anvisha [2.4K]

Answer:

D. (6) is the distance between 6 and 0, and the distance is negative from 6 to 0

Step-by-step explanation:

(6) means the number exists in the negative state. It is -6.

Option A - As it is -6, it cannot be greater than positive 6. So, it is incorrect.

Option B - As it is -6, it cannot be less than negative 6. So, it is wrong.

Option C - As it is -6, its distance cannot be 0 to 6, and it should not be positive.

Option D - As it is -6, its distance should be negative and the distance is from 6 to 0. Therefore, it is the correct answer.

7 0

3 years ago

Factor the trinomial. Factor out the GCF first.<br> 5x^2y - 30xy^2 - 35y^3

anzhelika [568]

Answer: $5x^2y - 30xy^2 - 35y^3=5y(x+y)(x-7y)$

Step-by-step explanation:

GCF = Greatest common factor.

For example: 6 is the GCF of 12 and 18.

The given expression: $5x^2y - 30xy^2 - 35y^3$

It can be written as

$5x^2y - (5\times6)x( y\times y) - (5\times7)(y^2\times y)$

Taking out common factor $5y$ , we get

$5y(x^2-6xy-7y^2)\\\\ =5y(x^2+xy-7xy-7y^2)\ \ [\because-6xy=xy-7xy]\\\\=5y(x(x+y)-7y(x+y))\\\\= 5y((x+y)(x-7y))\\\\=5y(x+y)(x-7y)$

Hence, $5x^2y - 30xy^2 - 35y^3=5y(x+y)(x-7y)$

3 0

3 years ago

Joe began to increase the speed of his car at 2:00 P.M. Since that time,the speed of Joes car has been steadily increasing by 1

Olegator [25]

Answer:

7 mins

Step-by-step explanation:

Current speed of Joes Car = 65.5 mph

We have to find the time interval for which the car exceeded the speed limit of 55 mph.

While, we are given that the speed of the car was constantly increasing, hence the speed over all increased from the limit of 55 mph = 65.50-55.00 = 10.50 mph

We are also given that Joes car was increasing speed at a constant rate of 1.50 mph for every passing minute. Hence

1.50 mph is increased in 1 minute

1 mph will be increase in $\frac{1}{1.5}$ minutes

Hence

10.50 mph will be increased in $\frac{1}{1.5} \times 10.50$ minutes

$= \frac{10.5}{1.5}$

$=7$

Hence joes car was exceeding the limit of 55 mph for 7 minutes.

8 0

2 years ago