Solve for w 8/5w =40 whats the answer , whats w its in a fraction w is by the fraction

Mathematics

1 answer:

densk [106]3 years ago

7 0

Answer:

So first, you have to isolate w. You can do this by getting rid of the 8/5.

This will get you to: w = 25

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Answer:

12 weeks.

Step-by-step explanation:

Keiths dog will need to lose 15 pounds to get down to 75 pounds. If he loses 1.25 pounds per week, it will take 12 weeks to get down to 75 pounds. To figure this out, you would use the equation:

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The inequality would look like this:

-2 (3x + 2) $\geq$ -6x-4

To begin to find the solutions, distribute the -2 throughout the set of parenthesis on the left side of the inequality by multiplying the -2 by each term in the set of parenthesis

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-6x -4 $\geq$ -6x-4

Begin to isolate x by performing the opposite operation of adding -6x on both sides of the inequality

0x -4 $\geq$ -4

Next perform the opposite operation by adding 4 on both sides of the inequality

0x $\geq$ 0

Now, I'm not exactly understanding how that can possibly work. So, I guess I didn't really help you. But add a comment so that we can talk about the problem :)

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PLEASE HELP ASAP 25 PTS TO RIGHT/BEST ANSWER

Novay_Z [31]

Subtract 1111 from both sides

5{e}^{{4}^{x}}=22-115e4x=22−11

Simplify 22-1122−11 to 1111

5{e}^{{4}^{x}}=115e4x=11

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{e}^{{4}^{x}}=\frac{11}{5}e4x=511

Use Definition of Natural Logarithm: {e}^{y}=xey=x if and only if \ln{x}=ylnx=y

{4}^{x}=\ln{\frac{11}{5}}4x=ln511

: {b}^{a}=xba=x if and only if log_b(x)=alogb(x)=a

x=\log_{4}{\ln{\frac{11}{5}}}x=log4ln511

Use Change of Base Rule: \log_{b}{x}=\frac{\log_{a}{x}}{\log_{a}{b}}logbx=logablogax

x=\frac{\log{\ln{\frac{11}{5}}}}{\log{4}}x=log4logln511

Use Power Rule: \log_{b}{{x}^{c}}=c\log_{b}{x}logbxc=clogbx
\log{4}log4 -> \log{{2}^{2}}log22 -> 2\log{2}2log2

x=\frac{\log{\ln{\frac{11}{5}}}}{2\log{2}}x=2log2

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