If you take the square root of a number squared number then they cancel each other out and the number stays the same i.e. √[(4)^2] would equal 4.
In this problem the square root and numbered squared cancel out to leave the problem as -2a.
The solution of this problem is -2a
Answer:
If the reindeer do not fight, there are 5!=120 ways to line them up in a straight line.
Out of these, Bloopin and Rudy are together in 4!=24 times. Similarly Rudy and Bloopin will be together 4!=24 times. So the number of ways they are not together is 120-24-24=72 ways.
Hope this helps. :)
Step-by-step explanation:
Spanish:
Si los renos no luchan, hay 5! = 120 formas de alinearlos en línea recta.
De estos, Bloopin y Rudy están juntos en 4! = 24 veces. De manera similar, Rudy y Bloopin estarán juntos 4! = 24 veces. Entonces, el número de formas en que no están juntas es 120-24-24 = 72 formas.
Espero que esto ayude :)
Answer:
a and d
Step-by-step explanation:
v and w are parallel lines
R is the transversal
Alternate exterior means on the opposite sides of the transversal and outside of the parallel linea
a and d are alternate exterior angles
Answer:
a₃₅ = 182
Step-by-step explanation:
There is a common difference d between consecutive terms, that is
d = 17 - 12 = 22 - 17 = 5
This indicates the sequence is arithmetic with n th term
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 12 and d = 5 , then
a₃₅ = 12 + (34 × 5) = 12 + 170 = 182
Answer:
the correct answer is d
Step-by-step explanation:
w(s)=weeks saved and 20s is the gain of 20 dollars every week. and the 95 is the starting amount that sam had