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Ksju [112]
3 years ago
7

.77 divided by 1369 to the nearst whole

Mathematics
2 answers:
LekaFEV [45]3 years ago
8 0
The answer is 0.00055837563 but if you were asked to write it the the nearest whole, it would be 0
Scorpion4ik [409]3 years ago
6 0
To the nearest whole number it would be 1
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Answer this pls asap
irina [24]

Answer:

351.68 cm^2

Step-by-step explanation:

We need to find the area of the frame itself. the radius of the inner circle is 12, but the frame has a radius of 4. You add 12 and 4 and you get 16. The formula for area of a circle is A=πr^2. So A= 3.14 x16^2. Then you have A= 3.14x 256 and you get 803.84. But we only want the area of the frame, so you have to get the area of the inner circle and subtract. You get A= 3.14 x 12^2. 3.14x144 is 452.16. 803.84-452.16 is 351.68. Hope this helped. :)

3 0
3 years ago
Read 2 more answers
Let f(x)=5x3−60x+5 input the interval(s) on which f is increasing. (-inf,-2)u(2,inf) input the interval(s) on which f is decreas
o-na [289]
Answers:

(a) f is increasing at (-\infty,-2) \cup (2,\infty).

(b) f is decreasing at (-2,2).

(c) f is concave up at (2, \infty)

(d) f is concave down at (-\infty, 2)

Explanations:

(a) f is increasing when the derivative is positive. So, we find values of x such that the derivative is positive. Note that

f'(x) = 15x^2 - 60


So,


f'(x) \ \textgreater \  0
\\
\\ \Leftrightarrow 15x^2 - 60 \ \textgreater \  0
\\
\\ \Leftrightarrow 15(x - 2)(x + 2) \ \textgreater \  0
\\
\\ \Leftrightarrow \boxed{(x - 2)(x + 2) \ \textgreater \  0} \text{   (1)}

The zeroes of (x - 2)(x + 2) are 2 and -2. So we can obtain sign of (x - 2)(x + 2) by considering the following possible values of x:

-->> x < -2
-->> -2 < x < 2
--->> x > 2

If x < -2, then (x - 2) and (x + 2) are both negative. Thus, (x - 2)(x + 2) > 0.

If -2 < x < 2, then x + 2 is positive but x - 2 is negative. So, (x - 2)(x + 2) < 0.
 If x > 2, then (x - 2) and (x + 2) are both positive. Thus, (x - 2)(x + 2) > 0.

So, (x - 2)(x + 2) is positive when x < -2 or x > 2. Since

f'(x) \ \textgreater \  0 \Leftrightarrow (x - 2)(x + 2)  \ \textgreater \  0

Thus, f'(x) > 0 only when x < -2 or x > 2. Hence f is increasing at (-\infty,-2) \cup (2,\infty).

(b) f is decreasing only when the derivative of f is negative. Since

f'(x) = 15x^2 - 60

Using the similar computation in (a), 

f'(x) \ \textless \  \ 0 \\ \\ \Leftrightarrow 15x^2 - 60 \ \textless \  0 \\ \\ \Leftrightarrow 15(x - 2)(x + 2) \ \ \textless \  0 \\ \\ \Leftrightarrow \boxed{(x - 2)(x + 2) \ \textless \  0} \text{ (2)}

Based on the computation in (a), (x - 2)(x + 2) < 0 only when -2 < x < 2.

Thus, f'(x) < 0 if and only if -2 < x < 2. Hence f is decreasing at (-2, 2)

(c) f is concave up if and only if the second derivative of f is positive. Note that

f''(x) = 30x - 60

Since,

f''(x) \ \textgreater \  0&#10;\\&#10;\\ \Leftrightarrow 30x - 60 \ \textgreater \  0&#10;\\&#10;\\ \Leftrightarrow 30(x - 2) \ \textgreater \  0&#10;\\&#10;\\ \Leftrightarrow x - 2 \ \textgreater \  0&#10;\\&#10;\\ \Leftrightarrow \boxed{x \ \textgreater \  2}

Therefore, f is concave up at (2, \infty).

(d) Note that f is concave down if and only if the second derivative of f is negative. Since,

f''(x) = 30x - 60

Using the similar computation in (c), 

f''(x) \ \textless \  0 &#10;\\ \\ \Leftrightarrow 30x - 60 \ \textless \  0 &#10;\\ \\ \Leftrightarrow 30(x - 2) \ \textless \  0 &#10;\\ \\ \Leftrightarrow x - 2 \ \textless \  0 &#10;\\ \\ \Leftrightarrow \boxed{x \ \textless \  2}

Therefore, f is concave down at (-\infty, 2).
3 0
3 years ago
PLEASE PLEEAASE HELP!! You have a 5-question multiple-choice test. Each question has four choices. You don’t know any of the ans
Rasek [7]
<span>The number of ways to permute three correct answers among five questions is 5Choose3 which is 5!/(3!*2!) which equals 10. We must then have the correct answer three times which happens .25 of the time, and two wrong answers 75 of the time. So the probability is 10*0.25^3*.75^2 which is 0.087890625 or roughly an 8.8% chance.</span>
5 0
3 years ago
Please help me with this. Please!
jonny [76]

Answer:

214

Step-by-step explanation:

A circle is 360 degrees

Arc EF is 146 degrees

EF + EDF = full circle

146 + EDF = 360

Subtract 146 from each side

146-146 +EDF = 360-146

EDF =214

4 0
3 years ago
3,4 and 5,12 find the slope
kirill115 [55]
It a diagujsudhdgdushe dhahshsue
8 0
3 years ago
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