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3 years ago

What is the value of the expression below when w=3?6w-9

Mathematics

1 answer:

Nikitich [7]3 years ago

6 0

Answer:

Step-by-step explanation:

Substitute w = 3 into the expression

6w - 9

= 6(3) - 9

= 18 - 9

= 9

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The explicit formula for the nth term of an arithmetic sequence is an = a1 + (n - 1) • d. What is the simple formula correspondi

BlackZzzverrR [31]

= -10 + (n - 1)*4
= -10 + 4n - 4
= 4n - 14

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3 years ago

In 1999 Daniel was 146 cm tall. He grew to be 176 cm by the year 2006. What was Daniel's rate of growth over this period of his

andreyandreev [35.5K]

Answer:

he grows by 5 cm every year between 1999 and 2006

Step-by-step explanation:

This is a arithmetic progression problem with the formula;

T_n = a + (n - 1)d

We are told that In 1999 Daniel was 146 cm tall. He grew to be 176 cm by the year 2006.

Thus;

a = 146

d = 2006 - 1999 = 7

Thus;

176 = 146 + (7 - 1)d

176 - 146 = 6d

30 = 6d

d = 30/6

d = 5 cm

Thus, he grows by 5 cm every year between 1999 and 2006

3 0

3 years ago

What fraction is 6 of 18

Leto [7]

Answer:

1/3

Step-by-step explanation:

6 of 18 = 6/18

Divide by 6, the GCF of the two numbers 6 and 18, to get 1/3.

6 is 1/3 of 18.

4 0

3 years ago

Read 2 more answers

At a used book sale, the number of books bought and the price paid by five different customers is shown in the table below. Odin

Arisa [49]

Answer:

Part A= 0.5

Step-by-step explanation:

7 0

2 years ago

Suppose you choose a team of two people from a group of n > 1 people, and your opponent does the same (your choices are allow

jonny [76]

Answer:

The number of possible choices of my team and the opponents team is

$\left\begin{array}{ccc}n-1\\E\\n=1\end{array}\right i^{3}$

Step-by-step explanation:

selecting the first team from n people we have $\left(\begin{array}{ccc}n\\1\\\end{array}\right) = n$ possibility and choosing second team from the rest of n-1 people we have $\left(\begin{array}{ccc}n-1\\1\\\end{array}\right) = n-1$

As { A, B} = {B , A}

Therefore, the total possibility is $\frac{n(n-1)}{2}$

Since our choices are allowed to overlap, the second team is $\frac{n(n-1)}{2}$

Possibility of choosing both teams will be

$\frac{n(n-1)}{2} * \frac{n(n-1)}{2} \\\\= [\frac{n(n-1)}{2}] ^{2}$

We now have the formula

1³ + 2³ + ........... + n³ = $[\frac{n(n+1)}{2}] ^{2}$

1³ + 2³ + ............ + (n-1)³ = $[x^{2} \frac{n(n-1)}{2}] ^{2}$

= $\left[\begin{array}{ccc}n-1\\E\\i=1\end{array}\right] = [\frac{n(n-1)}{2}]^{3}$

4 0

3 years ago