We can use the equation 45m < 481
we can replace m to see where it caps.
and the cap is 10.
we can replace m to check our work
45(10) < 481
450 < 481
if you add another student, it would go over the limit.
hope this helps :D
Answer:
for 20 number.
<AEB=142
<BEC=38
<DEC=142
<AED=38
Step-by-step explanation:
or, m<AEB+m<BEC=180(Straight line)
or, 6x-32+2x-20=180
or, 8x-52=180
or, x=29
replacing value of x
m<AEB=6×-32
=6*29-32
=142
m<BEC=2X-20
=2*28-20
=38
m<AED=m<BEC=38(Vertcally opposite angle)
m<DEC=m<AEB=142(Vertically opposite angle)
Answer:
There are 8 girls on the team.
Step-by-step explanation:
In this equation, we are being asked to find how many girls are on a 20 person team that has 12 boys.
We will use the variable g to represent girls.
We know that the sum of all the boys and girls on the team is 20, and that there are 12 boys, so lets write the equation out.
12 boys + g girls = 20 members
12 + g = 20
(12 + g) = (20)
(12 + g) - 12 = (20) - 12
g = 8
girls = 8
There are 8 girls on the team!
