X = or > -21/2 with the problem.
Answer:
72π
Step-by-step explanation:
The computation of the volume of the cone is shown below:
Here The radius of the base is one of the legs, therefore it is 6.
And, The height of the cone represent the other leg, therefore it is also 6.
Now as we know that
The volume of the cone is
= 1 ÷ 3 πr^2h
= 1 ÷ 3π 6^2 6
= π × 36 × 2
= 72π
Answer:
x^ -10
Step-by-step explanation:
x^2 * x ^ -12
We know that a^b * a^c = a^ (b+c)
x^2 * x^-12
x^(2+-12)
x^ -10
Answer:
y(t)''=3y(t)^2-(s2+13)
Step-by-step explanation:d[y(t)]/dt is the same thing as y'(t). Thus:
d[y'(t)]=y''(t); d[y(t)^3]=3.y(t)^(3-1)=3y(t)^2; and d[k.y(t)] is k, where k is a variable or constant that independs on y.
Use FOIL. (First, Outside, Inside, Last). Remember to combine like terms afterwards.
(6x - 9)(5x + 4)
(6x)(5x) = 30x²
(6x)(4) = 24x
(-9)(5x) = -45x
(-9)(4) = -36
30x² + 24x - 45x - 36
combine like terms
30x² + (24x - 45x) - 36 => 30x² - 21x - 36 (answer)
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(3x² + 2x)(x - 6)
3x²(x) = 3x³
3x(-6) = -18x
2x(x) = 2x²
2x(-6) = -16x
Combine like terms
3x³ + 2x² - 18x - 16x
3x³ + 2x² - 34x is your answer
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(2x² - 5x + 3)(4x³ - 1)
FOIL: Distribute each number in one parenthesis to all monomials in the other
4x³(2x²) = 8x^5
4x³(-5x) = -20x^4
4x³(3) = 12x³
-1(2x²) = -2x²
-1(-5x) = 5x
-1(3) = -3
8x^5 - 20x^4 +12x³ - 2x² + 5x -3 is your answer
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hope this helps
